View an ExampleQuestion HelpTranslate the staternentinto a conlidence interval. ApproximIate the level of conlideceIn a survey of 855 adults in a country 81 said being able to speak the language is at the core ct nationalidentily. The survey's margin of error is 4.2%The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curvebetween - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area.For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the areato the left of z, 3.13. rouding to four decimal placesArea to the left of zArea to the left of - z= 0.00090.9991Find the approximate value of the level of confidence c by solving for the pcsitive difference between the twoareasPress Continue to see more.

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Asked Dec 4, 2019
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How can you find the left area of  zc= -3.13and -zc values using a ti-83 calculator

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Question Help
Translate the staternentinto a conlidence interval. ApproximIate the level of conlidece
In a survey of 855 adults in a country 81 said being able to speak the language is at the core ct national
identily. The survey's margin of error is 4.2%
The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curve
between - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area.
For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the area
to the left of z, 3.13. rouding to four decimal places
Area to the left of z
Area to the left of - z
= 0.0009
0.9991
Find the approximate value of the level of confidence c by solving for the pcsitive difference between the two
areas
Press Continue to see more.
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View an Example Question Help Translate the staternentinto a conlidence interval. ApproximIate the level of conlidece In a survey of 855 adults in a country 81 said being able to speak the language is at the core ct national identily. The survey's margin of error is 4.2% The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curve between - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area. For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the area to the left of z, 3.13. rouding to four decimal places Area to the left of z Area to the left of - z = 0.0009 0.9991 Find the approximate value of the level of confidence c by solving for the pcsitive difference between the two areas Press Continue to see more.

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Expert Answer

Step 1

Follow the provided steps of Ti-83 calculator to find out the area to the left of -3.13

  1. Press 2nd then DISTR
  2. Select normalcdf(
  3. Press (-) which is to the left of Enter key > Type 1 > Press 2nd , EE (on comma key) and write 99.
  4. Type -3.13 and close the right bracket.
  5. Press Enter.
Step 2

The obtained output i...

TEXAS INSTRUMENTS
TI-83 Plus
normalcdf-1 e99
-3.13
8.740986195E-4
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TEXAS INSTRUMENTS TI-83 Plus normalcdf-1 e99 -3.13 8.740986195E-4

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