Vin (t) + R + Vout (t) 1 RC. equation (5) Vin(t) = cos(wt) equation (6) W = Wc = Fig. 1. A simple "lowpass" filter circuit Let C 0.047μF in the circuit of Fig. 1. Using equation (5) above, determine what value of R is required for the filter to have a cutoff frequency of fe = 340 Hz (wc = 2135 rads/sec). For Vin(t) given in equation (9), fe is the frequency at which Vout = ₂. 1
Vin (t) + R + Vout (t) 1 RC. equation (5) Vin(t) = cos(wt) equation (6) W = Wc = Fig. 1. A simple "lowpass" filter circuit Let C 0.047μF in the circuit of Fig. 1. Using equation (5) above, determine what value of R is required for the filter to have a cutoff frequency of fe = 340 Hz (wc = 2135 rads/sec). For Vin(t) given in equation (9), fe is the frequency at which Vout = ₂. 1
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter33: Alternating Current Circuits
Section: Chapter Questions
Problem 33.71AP: In Figure P33.71, find the rms current delivered by the 45.0-V (rms) power supply when (a) the...
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