void radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPS
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- JavaTimer.java: import java.util.Arrays;import java.util.Random; public class JavaTimer { // Please expand method main() to meet the requirements. // You have the following sorting methods available: // insertionSort(int[] a); // selectionSort(int[] a); // mergeSort(int[] a); // quickSort(int[] a); // The array will be in sorted order after the routines are called! // Be sure to re-randomize the array after each sort. public static void main(String[] args) { // Create and initialize arrays int[] a = {1, 3, 5}, b, c, d; // Check the time to sort array a long startTime = System.nanoTime(); quickSort(a); long endTime = System.nanoTime(); long duration = (endTime - startTime) / 1000l; // Output results System.out.println("Working on an array of length " + a.length + "."); System.out.println("Quick sort: " + duration + "us."); }…In Java languge (Duplicate Elimination) Write a program that reads in a series of first names and eliminates duplicates by storing them in a Set. Allow the user to search for a first name. Add a name to set, use end to terminate input: Search a name, use end to terminate searching: Sample output as follows:JavaTimer.java: import java.util.Arrays;import java.util.Random; public class JavaTimer { // Please expand method main() to meet the requirements.// You have the following sorting methods available:// insertionSort(int[] a);// selectionSort(int[] a);// mergeSort(int[] a);// quickSort(int[] a);// The array will be in sorted order after the routines are called!// Be sure to re-randomize the array after each sort.public static void main(String[] args) {// Create and initialize arraysint[] a = {1, 3, 5}, b, c, d;// Check the time to sort array along startTime = System.nanoTime();quickSort(a);long endTime = System.nanoTime();long duration = (endTime - startTime) / 1000l;// Output resultsSystem.out.println("Working on an array of length " + a.length + ".");System.out.println("Quick sort: " + duration + "us.");}// Thanks to https://www.javatpoint.com/insertion-sort-in-javapublic static void insertionSort(int array[]) {int n = array.length;for (int j = 1; j < n; j++) {int key = array[j];int…
- Implement in C Program 5.20 LAB: Word frequencies Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins with an integer indicating the number of words that follow. Assume that the list will always contain fewer than 20 words, and each word contains fewer than 10 characters. Ex: If the input is: 5 hey hi Mark hi mark the output is: hey - 1 hi - 2 Mark - 1 hi - 2 mark - 1 Hint: Use two arrays, one array for the strings and one array for the frequencies. #include <stdio.h>#include <string.h> int main(void) { /* Type your code here. */ return 0;}Use an array and two index variables. Write functions or methods push, pop, and sizeof. Then write a main function or method that will allocate the stack at n=10 and push some strings in ii, print out the size, and then pop some strings from it. Note make stack be be able to hold string variable type. javaimport java.util.Scanner;import java.util.ArrayList; public class UserIDSorting {// TODO: Write the partitioning algorithm - pick the middle element as the // pivot, compare the values using two index variables l and h (low and high), // initialized to the left and right sides of the current elements being sorted,// and determine if a swap is necessarypublic static int partition(ArrayList<String> userIDs, int i, int k) {} // TODO: Write the quicksort algorithm that recursively sorts the low and // high partitionspublic static void quicksort(ArrayList<String> userIDs, int i, int k) {} public static void main(String[] args) {Scanner scnr = new Scanner(System.in); ArrayList<String> userIDList = new ArrayList<String>(); String userID; userID = scnr.next();while (!userID.equals("-1")) {userIDList.add(userID);userID = scnr.next();}// Initial call to quicksort quicksort(userIDList, 0, userIDList.size() - 1); for (int i = 0; i < userIDList.size(); ++i)…
- in Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generatedGiven an array of strings strs, group the anagrams together. You can return the answer in any order. An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. Example 1: Input: strs = ["eat","tea","tan","ate","nat","bat"] Output: [["bat"],["nat","tan"],["ate","eat","tea"]] Example 2: Input: strs = [""] Output: [[""]].java getDup accepts an array and returns an int. If there is any element is duplicated, the method counts how many of those present in the array. Example : getDup(["1","2","aa"',"1"]) returns:2 ("1" is duplicated and there are two "1"s so return is 2) class Main { public static int getDup(String[] r) { } public static void main(String[] args) { Scanner in = new Scanner(System.in); String [] strs = new String[in.nextInt()]; for(int i=0; i < strs.length; i++) { strs[i] = in.next(); } System.out.println(getDup(strs)); } } hint: you will need a nested array the will run on the array we get from the method argument. inside the nested loop you will need to check if the main array element is equal to the current
- // MergeSortTest.java// Sorting an array with merge sort.import java.security.SecureRandom;import java.util.Arrays; public class MergeSortTest { // calls recursive sortArray method to begin merge sorting public static void mergeSort(int[] data) { sortArray(data, 0, data.length - 1); // sort entire array } // splits array, sorts subarrays and merges subarrays into sorted array private static void sortArray(int[] data, int low, int high) { // test base case; size of array equals 1 if ((high - low) >= 1) { // if not base case int middle1 = (low + high) / 2; // calculate middle of array int middle2 = middle1 + 1; // calculate next element over // split array in half; sort each half (recursive calls) sortArray(data, low, middle1); // first half of array sortArray(data, middle2, high); // second half of array // merge two sorted arrays after split calls…Debug C language int element(int arr[], int num) { in i, ele; ele = arr[0]; for (i = 1; i < num; i++) if (arr[i] > ele) ele = arr[i]; return ele; } main() { arr[] = {1, 24, 145, 20, 8, -101, 300}; int n = sizeof(arr)/sizeof(arr[0]); printf("element of array is %d", element(arr[], n)); }Write a program in java using two dimensional arrays. You should prompt the user toenter the number of rows and columns for your matrix. You should then prompt the userto enter values for each element of the matrix. Once the user has provided all the values for matrix, you should print the matrix and transpose of that matrix. A transpose of a matrix converts rows to columns and columns to rows.Example:Output: This program transposes a matrix.Output: Please enter the number of rows:User enters 2Output: Please enter the number of columns:User enters 3Enter value for row[0] column[0]: 9Enter value for row[0] column[1]: 1Enter value for row[0] column[2]: 2Enter value for row[1] column[0]: 72Enter value for row[1] column[1]: 3Enter value for row[1] column[2]: 6The matrix you entered is:9 1 272 3 6The transpose of this matrix has 3 rows and 2 columns and the transpose is:9 721 32 6