Vo(s) = S 5+s 3(5+5) 3 V015) = *£$ = (5² +85+18) (5+) s²+85 3 How? 5+85+18 3 3 [S+2.4.5+ 4+2 (S+2)² +2 √₂ √₂ (S+4)² + (12) Vols) = Vols) = vx LIT [eat sinbt] Vo(s) Inverse vo(t) LOT NOCNA SOLT [ 2 (FY (IT) (s+y)² + (√3)²) = (Sta) 45
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![3(5+5)
3(S+5)
s(s+85+18)
⇒ by voltage devision Rule.
Vo(s) = V X. S
ats
3(5+5)
3
Vols) =
*£*
(5² +85+18) (5+5) stos
3
How?
5+85+18
3
3
=
[S²+ 2.4.5 +47] + 2 (S+₂)³ +2
√2
√₂ (S+4)² + (√2)
VOIS)
Vols) =
-
Lit[eat sinbe]
Vo(s)
Invesse vo(t)
LOT
VOCW) = J.LT [2 (4) + (7)
√2
•
=
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- In the circuit given below, R = 14 Ω. The switch in the circuit moves from position A to position B at t = 0 (please note that the switch must connect to point B before it breaks the connection at A, a make-before-break switch). Determine i(t) for t > 0. a) i(t) = e–3.571t (0.726 sin(19.679t)) A b) i(t) = e–3.571t (4 cos(19.679t)) A c) i(t) = e–3.571t (4 cos(19.679t) – 0.726 sin(19.679t)) A d) i(t) = e–3.571t (4 cos(19.679t) + 0.726 sin(19.679t)) AA battery with a terminal voltage of 12V is connected to a circuit consisting of four 10 and one 5 resistor all in series. Assume the battery has negligible internal resistance. Calculate the current through each resistor. A. 1 A B. 0.2 A C. 0.3 A D. 0.4 A Calculate the RC time constant, τ of a circuit having a resistance of 15 MΩ and 3 010 ?? .A. 48 530 s B. 47 280 s C. 46 410 s D. 45 150 s ANSWERT 1 AND 2 ITEMS SHOW YOUR ENCODED SOLUTIONplss solve within 20mins An RL circuit has an emf of 5 volts, a resistance of 50 ohms, an inductance of 1 henry, and no initial current. Find the current in the circuit at time t = 2 ms. Express your answer in mA and round-off to three (3) decimal places. 6.915 mA 9.516 mA 5.916 mA 5.619 mA
- if you have answered this question pls do not reanswer, I just need confirmation. Va = 26V, Vb = 42V, Ic = 10mA. The circuit is in dc steady state. Use superposition. Considering ONLY the contribution of the voltage source, Va. Determine I3. Enter your answer in mA rounded to one decimal place.Given a parallel RLC circuit comprised of the following element: 63.92-ohm resistor, ideal inductor with reactance of 46.65 ohms; and a capacitor with reactance of 8.65 ohms. Compute for true power in watts given an ac voltage source of 100 cis 0 volts. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation. Use stored values.This is a LTI SYSTEM PROBLEM, please answer within 20 minutes. I'm really new at this and I'm having difficulty in getting the answer. Please explain and if possible give the solution also. The problem is The system y(t)=ln[x(t)+A] where A is a constant is The choices are in the photo
- Source voltage from Channel 1 output of oscilloscope and VR(t) and VL(t) voltages from Channel 2 output are desired to be observed by applying TTL signal to a series RL circuit with inductance value RL=270 mH, series R resistance 2.6 K and inductance internal resistance Rin=430 Ω. . The settings for the oscilloscope are as follows. Channel 1 Volt/div adjustment 2V Channel 2 Volt/div adjustment 2V Time/div=0.1ms Since the time t=5τ is 4.4 square units, a) If VL(t) voltage is desired to be observed from Channel 2, draw the required circuit diagram with oscilloscope channel connections. b) Plot the VR(t) and VL(t) waveforms to scale according to the 4V TTL source condition, showing the 5τ and τ times. Compare the τ value you obtained with the τ value you will theoretically calculate. c) If the unit square number of the peak value on the vertical axis at the end of t=5τ of the VR(t) voltage seen in Channel 2 is 1.4, find the current passing through the series RL circuit. d) Explain…Given a parallel RLC circuit comprised of the following element: 99.3-ohm resistor, ideal inductor with reactance of 66.76 ohms; and a capacitor with reactance of 19.7 ohms. Compute for true power in watts given an ac voltage source of 100 cis 0 volts. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation.A series connection of a 30-ohm resistor and a 100-mH inductor is connected across 240-V, 60-Hz supply. What will be the resulting equation of the current? a. i(t) = 7.04 sin(377t + 51.49°) b. i(t) = 7.04 sin(377t - 51.49°) c. i(t) = 4.98 sin(377t - 51.49°) d. i(t) = 4.98 sin(377t + 51.49°)
- Fill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5Please show your detailed solution Number 19 How much power is represented by a circuit in which the voltage and current equations are e = 180 sin314t and i = 42 sin 314t? A. 771 W C. 7560 W B. 3780 W D. 5346 W8. 7.8 In the circuit the voltage and current expressions are v=400e−5tV, t≥0+;i=10e−5tA, t≥0. 5. e) the time (in milliseconds) it takes to dissipate 80% of the initialstored energy.