W=127J q-1.35C V=? V=w/q3127/1.35-94.07V Question 6 At what distance from a positive charge of 8.421µC would the electric field strength be 3.91*10°N/C. Answer d%3? E=Kq/d?

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter7: Electric Potential
Section: Chapter Questions
Problem 81P: A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two...
icon
Related questions
icon
Concept explainers
Topic Video
Question

Could you kindly solve this and explain it to me with the equation?

W=127J
q-1.35C
V=?
V=w/q3127/1.35-94.07V
Question 6
At what distance from a positive charge of 8.421µC would the electric field strength be 3.91*10°N/C.
Answer
d%3?
E=Kq/d?
Transcribed Image Text:W=127J q-1.35C V=? V=w/q3127/1.35-94.07V Question 6 At what distance from a positive charge of 8.421µC would the electric field strength be 3.91*10°N/C. Answer d%3? E=Kq/d?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Displacement, velocity and acceleration
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning