Water is draining out of a tank so that the height of the water, h m , in time t minutes, satisfies the differential equation dh k h dt = − , where k is a positive constant. The initial height of the water is 2.25 m and 20 minutes later it drops to 1 m. a) Show that the solution of the differential equation can be written as ( )2 60 1600 t h − = . b) Find after how long the height of the water drops to 0.25 m.  In

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Author:James Stewart
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Chapter1: Functions And Models
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Water is draining out of a tank so that the height of the water, h m , in time t minutes,
satisfies the differential equation
dh k h
dt
= − ,
where k is a positive constant.
The initial height of the water is 2.25 m and 20 minutes later it drops to 1 m.
a) Show that the solution of the differential equation can be written as
( )2
60
1600
t
h

= .
b) Find after how long the height of the water drops to 0.25 m. 

In the attached image the prof. solves the equation. Please note the part in the rectangle. What is he doing here. Seems very slick!

 

de =kp?
(a)
dt
o whn teo P: bo0
I=B
dP= k dt
(000
At +
P
lo00
p*dP = Jkdt
tet
P= Z000
-p°= kt + C
: 44 +
200
kt t C
4A = -
a Att B
|
%3D
8000
lo00
8 -t
8000
P =
BooD
8-t
6) If t-8
P becomts mfinit-
P becomts negutivt
-la ta a
4.
Transcribed Image Text:de =kp? (a) dt o whn teo P: bo0 I=B dP= k dt (000 At + P lo00 p*dP = Jkdt tet P= Z000 -p°= kt + C : 44 + 200 kt t C 4A = - a Att B | %3D 8000 lo00 8 -t 8000 P = BooD 8-t 6) If t-8 P becomts mfinit- P becomts negutivt -la ta a 4.
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