We are told that the number of units of weekly output of a product is Q(x) = 200x + 5x² where x is the number of workers on the assembly line. Currently, there are 81 workers on the assembly line. We want to find Q(82) – Q(81) to see the actual change in the weekly output. Q(82) – Q(81) = [200( 82 v ) + 5( 82 v )?] – [200(81) + 5(81)²] %3D X - 49,005 Thus, the actual change in output from the addition of one worker is an increase of X units per week.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.2: Polynomial Functinos And Their Graphs
Problem 2E: Describe the end behavior of each polynomial. (a) y=x38x2+2x15 End behavior: y as x y as x (b)...
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We are told that the number of units of weekly output of a product is
Q(x) = 200x + 5x²
where x is the number of workers on the assembly line. Currently, there are 81 workers on the assembly line.
We want to find Q(82) – Q(81) to see the actual change in the weekly output.
Q(82) – Q(81) = [200( 82
v ) + 5( 82
v )?] – [200(81) + 5(81)²]
%3D
X - 49,005
Thus, the actual change in output from the addition of one worker is an increase of
X units
per week.
Transcribed Image Text:We are told that the number of units of weekly output of a product is Q(x) = 200x + 5x² where x is the number of workers on the assembly line. Currently, there are 81 workers on the assembly line. We want to find Q(82) – Q(81) to see the actual change in the weekly output. Q(82) – Q(81) = [200( 82 v ) + 5( 82 v )?] – [200(81) + 5(81)²] %3D X - 49,005 Thus, the actual change in output from the addition of one worker is an increase of X units per week.
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