We assign a complex number Am to each n-tuple of non-negative integers m = (m₁, ..., mn) arbitrarily. Show that there exists an f(x1,...,xn) E C (R") satisfying D"f(0) = Am for any m, where 0 = (0,..., 0). The one variable case was shown by Borel (1895). Later Rosenthal (1953) gave a simpler proof by considering 8(x)=ane-lanin!x2 xh n=0 is determined according to the given value of g)(0). Mirkil (1956) gave a proof for the n-dimensional case.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter6: Vector Spaces
Section6.2: Linear Independence, Basis, And Dimension
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We assign a complex number Am to each n-tuple of non-negative integers
m = (m₁, ..., mn) arbitrarily. Show that there exists an f(x1,...,xn) = C(R")
satisfying
Dm f(0) = Am
for any m, where 0 = (0,..., 0).
The one variable case was shown by Borel (1895). Later Rosenthal (1953)
gave a simpler proof by considering
8(x)= ane-lanin!x²
n=0
where an, is determined according to the given value of g)(0). Mirkil (1956)
gave a proof for the n-dimensional case.
Transcribed Image Text:We assign a complex number Am to each n-tuple of non-negative integers m = (m₁, ..., mn) arbitrarily. Show that there exists an f(x1,...,xn) = C(R") satisfying Dm f(0) = Am for any m, where 0 = (0,..., 0). The one variable case was shown by Borel (1895). Later Rosenthal (1953) gave a simpler proof by considering 8(x)= ane-lanin!x² n=0 where an, is determined according to the given value of g)(0). Mirkil (1956) gave a proof for the n-dimensional case.
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