We can assign a value to each character in a word based on their position in the alphabet (a = 1, b = 2, ..., z = 26). A balanced word is one where the sum of the values on the left side of the word equals the sum of the values on the right side. For odd-length words, the middle character (balance point) is ignored. Write a function that returns true if the word is balanced and false if it is not. Examples balance("zips") → true // "zips" = "zi|ps" "zips" = 26+9 | 16+19 = 35 35 = true balanced ("brake") → false // "brake" = "br|ke" = 2+18 | 11+5 = 2016 = false li

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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We can assign a value to each character in a word based on their
position in the alphabet (a = 1, b = 2, ..., z = 26). A balanced word
is one where the sum of the values on the left side of the word equals
the sum of the values on the right side. For odd-length words, the
middle character (balance point) is ignored.
Write a function that returns true if the word is balanced and false if
it is not.
Examples
balance("zips") → true
// "zips" = "zi|ps"
"zips" = 26+9 | 16+19
= 35 35 = true
balanced ("brake") → false
// "brake" = "br|ke" = 2+18 11+5 = 2016 = false
li
Transcribed Image Text:We can assign a value to each character in a word based on their position in the alphabet (a = 1, b = 2, ..., z = 26). A balanced word is one where the sum of the values on the left side of the word equals the sum of the values on the right side. For odd-length words, the middle character (balance point) is ignored. Write a function that returns true if the word is balanced and false if it is not. Examples balance("zips") → true // "zips" = "zi|ps" "zips" = 26+9 | 16+19 = 35 35 = true balanced ("brake") → false // "brake" = "br|ke" = 2+18 11+5 = 2016 = false li
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