We flip fair a coin twice. Consider the events A={HH, HT, TH} and B={HT, TT}. Then A and B are disjoint and also independent not disjoint and also independent disjoint and also non-independent not disjoint and also non-independent An experiment can result in one of the four equally likely simple events, E1, E2, E3, E4. The Events A and B are defined as follows, A:{E1,E2} P(A) = 0.5 B:{E1, E2, E4} P(B)=0.75. Then P(A∪B) = 1 P(A∩B) = 0.375 P(A|B) = 2/3 P(B|A) = 2/3
We flip fair a coin twice. Consider the events A={HH, HT, TH} and B={HT, TT}. Then A and B are disjoint and also independent not disjoint and also independent disjoint and also non-independent not disjoint and also non-independent An experiment can result in one of the four equally likely simple events, E1, E2, E3, E4. The Events A and B are defined as follows, A:{E1,E2} P(A) = 0.5 B:{E1, E2, E4} P(B)=0.75. Then P(A∪B) = 1 P(A∩B) = 0.375 P(A|B) = 2/3 P(B|A) = 2/3
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
Related questions
Question
We flip fair a coin twice. Consider the events A={HH, HT, TH} and B={HT, TT}. Then A and B are
|
disjoint and also independent |
|
not disjoint and also independent |
|
disjoint and also non-independent |
|
not disjoint and also non-independent |
An experiment can result in one of the four equally likely simple events, E1, E2, E3, E4. The Events A and B are defined as follows,
A:{E1,E2} P(A) = 0.5 B:{E1, E2, E4} P(B)=0.75. Then
|
P(A∪B) = 1 |
|
P(A∩B) = 0.375 |
|
P(A|B) = 2/3 |
|
P(B|A) = 2/3 |
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