We have that y*n+1=y*n=y*. Using the given model: yn+1 = byn(1-yn), we find that y* = 1-1/b and y* = 0 are fixed points. I have the function: def main(b,yInit,n): out=np.zeros((n,1)) y = yInit for i in range(n): out[i] = y y = b*(1-y)*y return out The graph model of this would depend both on the value of the initial population (y*) and choice of b. I need to graph this in python using interactive sliders widget [from matplotlib.widgets import slider], where one slider will control b value (x-axis) and another for y value (y-axis). I have the skeleton code for the sliders but have no idea how to graph this equation with it. (y* = between 0 to 1, b = 0 to 4)

We have that yn+1=yn=y. Using the given model: yn+1 = byn(1-yn), we find that y = 1-1/b and y* = 0 are fixed points. I have the function: def main(b,yInit,n): out=np.zeros((n,1)) y = yInit for i in range(n): out[i] = y y = b(1-y)y return out The graph model of this would depend both on the value of the initial population (y) and choice of b. I need to graph this in python using interactive sliders widget [from matplotlib.widgets import slider], where one slider will control b value (x-axis) and another for y value (y-axis). I have the skeleton code for the sliders but have no idea how to graph this equation with it. (y = between 0 to 1, b = 0 to 4)

Operations Research : Applications and Algorithms

4th Edition

ISBN:9780534380588

Author:Wayne L. Winston

Publisher:Wayne L. Winston

Chapter11: Nonlinear Programming

Section11.3: Convex And Concave Functions

Problem 15P

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