We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces up. What is the probability p that i + j = 6, provided that at least one of i and j is even? p = 0.0741 How was the correct answer of 0.0741 attained?

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 16E
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How was the correct answer of 0.0741 attained?

We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces
up. What is the probability p that i + j = 6, provided that at least one of i and j is even?
p = 0.0741
How was the correct answer of 0.0741 attained?
Transcribed Image Text:We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces up. What is the probability p that i + j = 6, provided that at least one of i and j is even? p = 0.0741 How was the correct answer of 0.0741 attained?
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