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# we want the square root of 17 for example g = 4                 # our guess is 4 initially error = 0.0000000001  # we want to stop when we are this close while abs(n - (g**2)) > error:   g = g - ((g**2 - n)/(2 * g)) # g holds the square root of n at this point   Implement this algorithm in a function sqR

# we want the square root of 17 for example g = 4                 # our guess is 4 initially error = 0.0000000001  # we want to stop when we are this close while abs(n - (g**2)) > error:   g = g - ((g**2 - n)/(2 * g)) # g holds the square root of n at this point   Implement this algorithm in a function sqR

C++ for Engineers and Scientists
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter7: Arrays
Section: Chapter Questions
Problem 15PP: (Computation) A magic square is a square of numbers with N rows and N columns, in which each integer...
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The following code implements Newton's algorithm for finding the square root of a number using repetition:

n = 17                # we want the square root of 17 for example
g = 4                 # our guess is 4 initially
error = 0.0000000001  # we want to stop when we are this close
while abs(n - (g**2)) > error:
  g = g - ((g**2 - n)/(2 * g))
# g holds the square root of n at this point  

Implement this algorithm in a function sqRoot(n), that returns the square root using recursion.

Assume that the function will be called with positive numbers only.

Note: Your initial guess cannot be zero!

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