We wish to gather some information relating to the average time a hospitalized Eagle Flu patient remains in the hospital. We randomly sample 16 cured formerly hospitalized Eagle Flu patients and these were the number of days spent in the hospital: 6.09, 8.04, 6.43, 8.58, 10.34, 5.40, 9.87, 9.24, 9.18, 5.06, 5.39, 5.89, 11.91, 8.94, 5.68, 9.85 Many surveys of flu hospital stays show that hospitalization length is normally distributed. So, we assume that our sample comes from a normal population with unknown mean of μ days and an unknown standard deviation of σ days. We would like to test whether the average hospital stay length is less than 8.1 days.. The null hypothesis is thus H0:μ=8.1 . We will test this against the alternative Ha We want to test at the 8% level. Let x = the sample mean and s = the sample standard deviation. f) Calculate the critical value, tstar, for your test.(negative value)
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
We wish to gather some information relating to the average time a hospitalized Eagle Flu patient remains in the hospital. We randomly sample 16 cured formerly hospitalized Eagle Flu patients and these were the number of days spent in the hospital:
6.09, 8.04, 6.43, 8.58, 10.34, 5.40, 9.87, 9.24, 9.18, 5.06, 5.39, 5.89, 11.91, 8.94, 5.68, 9.85
Many surveys of flu hospital stays show that hospitalization length is normally distributed. So, we assume that our sample comes from a normal population with unknown mean of μ days and an unknown standard deviation of σ days. We would like to test whether the average hospital stay length is less than 8.1 days..
The null hypothesis is thus
. We will test this against the alternative Ha
We want to test at the 8% level.
Let x = the sample mean and s = the sample standard deviation.
f) Calculate the critical value, tstar, for your test.(negative value)
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
