What are the maximum and minimum number of rows returned by the R1 right outer join R2? a. Min = rows in R2, max = rows in RI * rows in R2 b. Min = 0, max = rows in R1 + rows in R2 c. Min = 0, max = (rows in R1 + rows in R2) - 1 d. Min = rows in R2, max = (rows in RI + rows in R2) - I
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What are the maximum and minimum number of rows returned by the R1 right outer join R2?
a. Min = rows in R2, max = rows in RI * rows in R2
b. Min = 0, max = rows in R1 + rows in R2
c. Min = 0, max = (rows in R1 + rows in R2) - 1
d. Min = rows in R2, max = (rows in RI + rows in R2) - I
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- What are the maximum and minimum number of rows returned by the RI right outer join R2? a. Min = rows in R2, max = rows in RI * rows in R2 b. Min = 0, max = rows in RI + rows in R2 c. Min = 0, max = (rows in RI + rows in R2) - 1 d. Min = rows in R2, max = (rows in RI + rows in R2) — 1In cell H2, get the unique Area values using UNIQUE(). In column I, use COUNTIF() to get the count of each Area. Pass the data range from A2 to A45 as absolute addresses, and the filter criteria from H2 to H9. In column J, use COUNTIFS() to get the count of each area with more than 20 Swallow-tails. the first two arguments are the same as the previous step, then add a condition for column D to be greater than 20. Area Locality Skipper Swallowtail White-yellow Blue Brush-footed Area Count of Area Count of Area with 20 Swallowtails Indian Subcontinent Indian Subcontinent 307 94 99 458 482 Western Himalaya Western Himalaya 63 31 42 129 152 Western Himalaya Kangra Hills 25 23 37 56 87 Western Himalaya Shimla Hills 41 21 34 88 115 Western Himalaya Dehradun Valley 22 11 19 42 54 Western Himalaya Mussoorie Hills 54 23 32 88 126 Western Himalaya Mussoorie Town 14 10 13 44 65 Western Himalaya Kumaon Hills 52 26 37 109 147…Use the "College" data set from the package "ISLR", do the following: Get familiar with the data set. How many variables the data set has? What is the class of the variable "Private"? Add a new column "Enroll.rate" which is the ratio of Enroll v.s. Accept, to the data set. What are the top 10 Universities in terms of "Enroll.rate" (highest student enrollment ratio)? Get a new data frame "Mysubset" with all rows with an "Outstate" fee between 8000-9000 USD. solve using r code
- convert UNF for 1NF to 2NF to 3NF, progressively. UNF:Order(OrderID, OrderDate, CustID, CustName, CustPhone, CCNum, CCExpDate, CCBank, BnkContName, BnkContPhone, CustEmail, OrderIP, SiteRefFrom, ShipStreet, ShipCity, ShipSt, ShipZip, OrderLineNum, ItemID, ItemName, ItemDesc, ItemQtyOrdered,ItemListPrice, ItemSalePrice, ItemQtyShip, ShipCharge, Tax, TotalDue)I need help with this question two parts, please. C.) Add the following numbers to a 5-entry hash table using separate chaining to resolve collisions. Stop before adding an item that would result in α > 3.0. This means you might not use all the numbers. (Spoiler alert: you won't use them all.) 39 68 60 71 83 52 99 55 49 77 58 26 76 66 37 28 For the hash function, simply take the number mod the table size. In 5 blanks, write the list of numbers that would end up at that entry in the table, separated by spaces. If there is no number at that location, write empty. D.) Add the following numbers to an 11-entry hash table using separate chaining to resolve collisions. Stop before adding an item that would result in α > 3.0. This means you may not use all the numbers. 39 68 60 71 83 52 99 55 49 77 58 26 76 66 37 28 For the hash function, simply take the number mod the table size. In 11 blankS, write the list of numbers that would end up at that entry in the table, separated by…please delete X AREAS AND SEND ME
- I need help with this question, please. Parts A and B A.) Add the following numbers to an 11-entry hash table using linear probing to resolve collisions. Stop before adding an item that would result in α > 0.75. This means you might not use all the numbers. (Spoiler alert: you won't use them all.) 39 68 60 71 83 52 99 55 49 77 58 26 76 66 37 28 For the hash function, simply take the number mod the table size. In 11 blanks, write the number that would end up at that entry in the table. If there is no number at that location, write empty. B.) Add the following numbers to a 23-entry hash table using linear probing to resolve collisions. Stop before adding an item that would result in α > 0.75. This means you may not use all the numbers. 39 68 60 71 83 52 99 55 49 77 58 26 76 66 37 28 For the hash function, simply take the number mod the table size. In 23 blanks, write the number that would end up at that entry in the table. If there is no number at that location, write…Which of the following statements about hash pointers in Blockchain is CORRECT? A. A hash pointer is only used to retrieve the information. B. A hash pointer is only used to verify that the information in the previous block hasn't been changed. C. In the blockchain, the head of the list is a regular hash‐pointer that points to the first data block created in the network. D. In the blockchain, if an attacker tampers a block without modifying other blocks, then we cannot detect the change.Consider the following matrix: P = [3 6 9 12; 4 8 12 16; 3 6 9 12] What Octave command will you use to change all the values in the third column to 2?
- Try switching the joins pthread_join(tid2, NULL); pthread_join(tid1, NULL); Do you see any difference? Please report if and why you do or do not see any difference in terms of the randomness in the result of the shared resource. In the inc_dec_resource() function, implement mutual exclusion (pthread_mutex_lock) to ensure that the result becomes 0 every time when you execute your program. Put your updated code in the report (highlighted) and show your screenshot of the execution by running the script three time using $ time ./shared_resource_mutex. Hint: Your loop is incrementing/decrementing the resource which should be protected by each thread while it is executing that portion. #include <stdio.h> #include <pthread.h> #define iterations 300000000 long long shared_resource = 0; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; // Thread function to modify shared resource void* inc_dec_resource(void* arg){ //get the pointer from main thread and dereference it…Try switching the joins pthread_join(tid2, NULL); pthread_join(tid1, NULL); Do you see any difference? Please report if and why you do or do not see any difference in terms of the randomness in the result of the shared resource. In the inc_dec_resource() function, implement mutual exclusion (pthread_mutex_lock) to ensure that the result becomes 0 every time when you execute your program. Put your updated code in the report (highlighted) and show your screenshot of the execution by running the script three time using $ time ./shared_resource_mutex. Hint: Your loop is incrementing/decrementing the resource which should be protected by each thread while it is executing that portion. /* Compile: gcc -o shared_resouce_mutex shared_resource_mutex.c -lpthread Execute: ./shared_resource_mutex */ #include <stdio.h> #include <pthread.h> #define iterations 300000000 long long shared_resource = 0; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; // Thread function to…why when add new index in python data frame its make all columns nan and when I remove it not make column nan ? ex ) I create data frame with index [f1 t0 f30] when I create to f9 its ok all but when add f10 make all before data null?