Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=16 and n2=23. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled standard deviation, sp. For sample 1: s1=7.4 and x¯1=49 For sample 2: s2=6.9 and x¯2=53 What are the test statistic (t) and the degrees of freedom to perform this test? Select the correct answer below: If sp=7.107, then t=16−23(7.107) 116+123√≈−3.03 df=37 If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97 df=37 If sp=7.107, then t=49−53(7.107) 149+153√≈−2.84 df=39 If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73 df=37 If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73 df=39 If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97 df=39
Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=16 and n2=23. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled standard deviation, sp. For sample 1: s1=7.4 and x¯1=49 For sample 2: s2=6.9 and x¯2=53 What are the test statistic (t) and the degrees of freedom to perform this test? Select the correct answer below: If sp=7.107, then t=16−23(7.107) 116+123√≈−3.03 df=37 If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97 df=37 If sp=7.107, then t=49−53(7.107) 149+153√≈−2.84 df=39 If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73 df=37 If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73 df=39 If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97 df=39
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=16 and n2=23. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled standard deviation, sp.
- For sample 1: s1=7.4 and x¯1=49
- For sample 2: s2=6.9 and x¯2=53
Select the correct answer below:
If sp=7.107, then t=16−23(7.107) 116+123√≈−3.03
df=37
df=37
If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97
df=37
df=37
If sp=7.107, then t=49−53(7.107) 149+153√≈−2.84
df=39
df=39
If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73
df=37
df=37
If sp=7.107, then t=49−53(7.107) 116+123√≈−1.73
df=39
df=39
If sp=7.107, then t=16−23(7.107) 149+153√≈−4.97
df=39
df=39
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