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About INELASTIC collisions: (all questions are related to each other.) Please answer it short and easy to understand.
What happens when two cars of equal mass hit each other at the same velocity?
What happens if you keep the velocities the same but you double the mass of one car? (include what direction the cars go)
From the question above, what happens to their combined velocity?
Can you cancel out the effect of the greater mass of one car? Explain how.
What happens if both cars are traveling the same direction but the faster car from behind hits the slower moving car ahead? (include what direction the cars go)
- From #10 above, what happens to their combined velocity?
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- a ball (1) of 1kg moving at 1m/s strikes a stationary 1kg ball(2). Ball 1 stops, but ball 2 moves away at 1 m/s. A: is momentum conserved ? show proof B: is KE conserved? show your proof C: is this an example of an elastic collision or an inelatic collision?Given 2 identical marbles each of mass M traveling together a speed V what is the total linear momentum of this 2 marble system? what is the total kinetic energy? If the 2 marbles from the previous question strike three stationary marbles (as in your previous tests), what is the total linear momentum of the marble(s) that are in motion after the collision? What is the total kinetic energy?A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Fourth Time I'm asking Bartleby for help with this question, please explain in the diagram in detail please, step by step. ) (For some reason, one of the variables turns from 0.3 into 0.7 m/s, please explain) (If you cannot work with a rebound speed of 0.3, use 0.2)
- A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Third time I'm asking Bartleby for help with this question, please explain in the diagram in detail please)A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Fifth Time I'm asking Bartleby for help with this question, please explain in the diagram in detail please, step by step. ) (For example. for some reason, one of the variables turns from 0.3 into 0.7 m/s, please explain how and why) (Please lable velocities, masses ex. properly as which ones are the initials, finals, which mass belongs to which one.)About INELASTIC collisions: (all questions are related to each other.) Please answer it short and easy to understand. What happens if you keep the velocities the same but you double the mass of one car? (include what direction the cars go) From the question above, what happens to their combined velocity?
- A puck of mass m, moving at a speed of v1 collides with an identical mass stationary puck. After the collision, one puck moves off at an angle φ1 with a speed of v1’, and the other puck moves off at an angle φ2 with a speed of v2’. a) What are the speeds v1’ and v2’ if φ1 + φ2 = 90o? Express your answers in terms of v1 and φ1. b) Is the collision inelastic or (totally) elastic? Support your answer with a calculation.Hello can you help me solve this problem with complete solution and illustration? *A 40kg boy is sliding on a horizontal and frictionless surface with an initial momentum of 90J due east. When t=0, a force, a function of time, F=8.20t is applied to the boy due west. a) at what value of t will result in the momentum of the boy 60J due west? b) what is the acceleration of the boy at the time computed in letter a?Particle A of mass m, initial velocity 20i (m/s) has a collision with a stationary particle B of mass 2m. After collision, VA(final)=10i+5j (m/s) I need help understanding how does the i and j effect the formula for collision problems? I know the usual collision probleam steps but don't understand how this would effect the steps to solve the questions asked from this scenerio such as finding VB(final) if the system linear momentum is conserved in both directions. or calculating what the velocities of center of the system are before and after collision?
- How can we get/derive the second law of motion from the impulse-momentum theorem? Provide comprehensive explanation and derivation.For all the collisions in this lab, what can you conclude about the sum of the changes in momentum for the objects (Δp1 + Δp2 for Parts 1 and 2 and Δp1 + Δp2 + Δp3 for Part 3)? Does this agree with the Law of Momentum Conservation? Show why or why not.In each trial, use the mass of the cart and velocities to calculate the change in momentum. In each trial, use the force and time to calculate the impulse. 2. Calculate the percent difference between the change in momentum and the impulse. Take the difference divided by the average times 100%. How close are your values? Does your data support the impulse-momentum theorem? 3. When you used two rubber bands, did you tie them end-to-end or side-by-side? What effect did this have on the time of the impulse? What affect did this have on the size of the force? What is a general rule about force and time from these observations?