In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of theC-H is in the direction ofA = î + Î +Rand an adjacent C-H bond is at the directionB=î-7-R.results to an angular bond of approximately 109° for a static frozen molecule.However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to varyslightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to beA = 1.07i + 0.83j + 0.81kB = 1.03i + -0.99j + -0.85kWhat is the angle (in degrees) between the bonds based on this new data?Note: Only 1% of error is permitted for the correct answer.

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What is the angle (in degrees) between the bonds based on this new data?

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter15: Oscillatory Motion

Section: Chapter Questions

Problem 48CP: A smaller disk of radius r and mass m is attached rigidly to the face of a second larger disk of...

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A smaller disk of radius r and mass m is attached rigidly to the face of a second larger disk of radius R and mass M as shown in Figure P15.48. The center of the small disk is located at the edge of the large disk. The large disk is mounted at its center on a frictionless axle. The assembly is rotated through a small angle from its equilibrium position and released. (a) Show that the speed of the center of the small disk as it passes through the equilibrium position is v=2[Rg(1cos)(M/m)+(r/R)2+2]1/2 (b) Show that the period of the motion is v=2[(M/2m)+R2+mr22mgR]1/2 Figure P15.48
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=I hut + J hut + K hut and an adjacent C-H bond is at the direction B=I hut - J hut - K hut results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k What is the angle (in degrees) between the bonds based on this new data?
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=i+j+k and an adjacent C-H bond is at the direction B=i-j-k results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.06i + 0.98j + 0.9k B = 0.83i + -0.81j + -0.87k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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