What is the best case scenario?What is the exact number of operations for the best case scenario in terms of n and m?What is the big-oh for the best case scenario?What is the worst case scenario?What is the exact number of operations for the worst case scenario in terms of n and m?What is the big-oh for the worst case scenario? Consider the following algorithm tha finds a row where every entry is x in a 2-D array. Assumethat (a) the array has n rows and m columns, and that (b) the comparison on line 3 countstowards the running time.01 FOR every row in the arrayFOR every column in the arrayIF [row] [column]0203'x' THEN04IF column is the last THEN05DISPLAY found row06ENDIF07ELSE08move on to the next row09ENDIF10ENDFOR11 ENDFOR

The given algorithm is a 1FOR every row in the array 2 FOR every column in the array 3 IF…

What is the best case scenario? What is the exact number of operations for the best case scenario in terms of n and m? What is the big-oh for the best case scenario? What is the worst case scenario? What is the exact number of operations for the worst case scenario in terms of n and m? What is the big-oh for the worst case scenario?

What is the best case scenario? What is the exact number of operations for the best case scenario in terms of n and m? What is the big-oh for the best case scenario? What is the worst case scenario? What is the exact number of operations for the worst case scenario in terms of n and m? What is the big-oh for the worst case scenario?

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter6: Arrays

Section: Chapter Questions

Problem 17RQ

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Have a look at the array below. We are trying to do quicksort on this array to sort it in ascending order. We wrote an algorithm that always takes the middle element as pivot. How the array will look like after first iteration(write in this format: 11,12,13,14,15)Array: 525 76 980 290 38 77 746 266 375 . Show the simulation in handwritten paper. Which sorting algorithm (Insertion, Merge, Quick) perform same in all (best, average and worst case) ?
A) Starting with a dynamic array of length = 32 and numElements = 30, the length after we execute 90 insert at end operations is [answer]Group of answer choices 120 122 128 none of the above B) In each of the following cases, we start with a dynamic array of length = 128 and numElements = 64. After we execute 30 delete last operations, the number of elements isand the length isAfter we execute 32 delete last operations, the number of elements isand the length isAfter we execute 60 delete last operations, the number of elements isand the length is no hand written
Given an array as follows5 4 9 10 2 8 1 3 7 6 Suppose we partition this array using quicksort's partition function and using 5 for the pivot. A) Draw the resulting array after the partition finishes.B) The following is an array which has just been partitioned by the first step of quicksort:3 0 2 4 5 8 7 6 9Give all the elements that could be the pivot? (There may be more than one possibility!) PLEASE HELP WITH PART A AND B AND SHOW WORK!!
Given an array of integers arr, sort the array by performing a series of pancake flips. In one pancake flip we do the following steps: Choose an integer k where 1 <= k <= arr.length. Reverse the sub-array arr[0...k-1] (0-indexed). For example, if arr = [3,2,1,4] and we performed a pancake flip choosing k = 3, we reverse the sub-array [3,2,1], so arr = [1,2,3,4] after the pancake flip at k = 3. Print out the k-values corresponding to a sequence of pancake flips that sort arr. Example 1: Input: arr = [3,2,4,1] Output: 4, 2, 4, 3 Explanation: We perform 4 pancake flips, with k values 4, 2, 4, and 3. Starting state: arr = [3, 2, 4, 1]. After 1st flip (k = 4): arr = [1, 4, 2, 3] After 2nd flip (k = 2): arr = [4, 1, 2, 3] After 3rd flip (k = 4): arr = [3, 2, 1, 4] After 4th flip (k = 3): arr = [1, 2, 3, 4], which is sorted. Another potential solution is: Output = 3, 4, 2, 3, 1, 2, 1, 1 with a similar explanation. All potential solutions that solve the problem are…
Let A and B be two arrays of length n, each containing a random permutation of the numbers from 1 to n. An inversion between the two permutations A and B is a pair of values (x, y) where the index of x is less than the index of y in array A, but the index of x is more than the index of y in array B. Design an algorithm which counts the total number of inversions between A and B that runs in O(n log n) time.
Given an integer array [A], efficiently find a descending sorted triplet such that: A[i]> A[i]> A[k] and 0 <=i<j <k <n, where n is the array size. For example, Input: A[] = {9, 1, 6, 7, 3, 4, 5) Output: Any one of the following triplets: (9, 7,5) (9, 7, 4) (9, 7, 3) (9, 6, 5) (9, 6, 4) (9, 6, 3) a) Design a brute-force algorithm to solve this problem complexity of your solution b) Design a more efficient algorithm to do the same task with less complexity and analyse the complexity of your solution. c) Develop a python code to implement your efficient algorithm. depend on the correctness of the code, indentation, comments, test-case] d) Prepare a brief report (250 words) comparing the two algorithms
: In searching an element in an array, linear search can be used, even though simple to implement, but not efficient, with only O(n) time complexity. Assuming the array is already in sorted order, modify the search function below, using a better algorithm, so the average time complexity for the search function is O(log n). include <iostream> using namespace std; int search(int al), int s, int v) { 1/ Modify below codes. for (int i = 0; i <s; i++) { if (a[i] = v) return i; return -1; int main() { int intArray:10] = { 5, 7, 8, 9, 10, 12, 13, 15, 20, 34); // Search for element '12' in 10-elements integer array. cout << search(intArray, 10, 12); // '5' will be printed out. // Search for element '35' in 10-elements integer array. cout << search(intArray, 10, 35); // '-1' will be printed out. // Index '-l' means that the element is not found. return 0;
Imagine that we want to keep track of friendships between n people. We can do this with an array of size nXn. Each row of the array represents the friends of an individual, with the columns indicating who has that individual as a friend. For example, if person j is a friend of person i, then we place a mark in column j of row i in the array. Likewise, we should also place a mark in column i of row j if we assume that friendship works both ways. What will be the space complexity of this problem
Take an array of length n where all the numbers are nonnegative and unique. Find the element inthe array possessing the highest value. Split the element into two parts where the first part containsthe next highest value in the array and the second part holds the required additive entity to get thehighest value. Return the array index value. Consider the negative numbers as well.Input: [4, 8, 6, 3, 2]Output: [4, 6, 2, 6, 3, 2]
Given an array A containing N numbers. The problem is to find the minimum gcd among all non-decreasing subarrays. Note: Gcd of k number is the greatest number which divides all k numbers. Example 1: Input : arr[] = {1, 2, 3, 2, 4, 1, 7} Output : 1 Explanation : Some non decreasing subarrays are - {1, 2, 3} gcd = 1, {2, 4} gcd = 2, {1, 7} gcd = 1, minimum gcd = 1
Please help me with this algorithm question. suppose we modified the QuickSort algorithm such that we run InsertionSort on the first 10% of A in the Partitionmethod. You may assume the selection of the pivot will be the last element in the range[p, r]. What would be the best and worst case running time of this new algorithm? Explainyour reasoning. // quickSort() method for integer array public void quickSort(int[] A, int p, int r) { if(p < r) { int q = partition(A, p, r); quickSort(A, p, q - 1); quickSort(A, q + 1, r); } } // partition() method for integer array public int partition(int[] A, int p, int r) { int x = A[selectPivot(A, p, r)]; int i = p - 1; for(int j = p; j < r; j++) { if(order) { if(A[j] > x) { i = i + 1; exchange(A, i, j); } } else { if(A[j] <= x) {…
s algorithm for finding all occurrences of a sequence in anothersequence using the suffix array of the latter sequence can be implemented inPerl in a straightforward way, as shown in the following Perl script. Recallthat the suffix array of a sequence of length n will be a permutation of arraypositions 0, 1, . . . , n − 1, because Perl arrays do not start with position 1 but,rather, with position 0.