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- Write the following code in java. Data races occur when there is insufficient synchronisation around composite operations. Write a short program that illustrates a data raceI need help with this question of Data Structures and Algorithmns 1) True or False a) If g1(n) = O(f1(n)) and g2(n) = O(f2(n)), then g1 x g2 = O(f1(n) x f2(n)) (True or False) b) If f(n) = logan and g(n) = logbn , then f(n) = Θ(g(n)) (True or False)Question 1) Implement Merge sort and Quick sort on a programming language of your choice. Evaluate their performance for the following input sizes:1)1002)10003) 10000004) 100000005) 1000000000You need fill the following table with the running times of each algorithm on your pc, the TABLE IS SHOWN IN THE IMAGE, PLEASE DO NOT ANSWER IF YOU CANNOT FILL IT.
- Question 1) Implement Merge sort and Quick sort on a programming language of your choice. Evaluate their performance for the following input sizes:1)1002)10003)10000004)100000005)1000000000You need fill the following table with the running times of each algorithm on your pc.I need help with this question of Data Structures and Algorithmns with explanation 1) True or False a) If g1(n) = O(f1(n)) and g2(n) = O(f2(n)), then g1 x g2 = O(f1(n) x f2(n)) (True or False) b) If f(n) = logan and g(n) = logbn , then f(n) = Θ(g(n)) (True or False)Compile the following C code snippet with optimization level O1 using armv7-a clang 11.0.1. a)Which register(s) are saved before entering the recursive call? Explain why. (Hint: the registers have their special purposes). b)Next modify line 2 from (n == 1) to (n == 0), Explain what has been changed? int foo2(int n) { if (n == 1) { return 1; } else { return n + foo2(n - 1); } }
- Someone tries to fix the stack based buffer overflow problem as follows, is it secure now? why?why not? Are there any other issues within the function's implementation below? Please explain your reasoning. int bof(char *str, int size) { char *buffer = (char *) malloc(size); strcpy(buffer, str); return 1; }model small .stack .data string db "ODD EVEN$" string2 db "Input:$" .code org 100h start: main proc mov ax,03 int 10h mov ax,@data mov ds,ax mov ah,9 lea dx,string int 21h call nlcr mov ah,9 lea dx,string2 int 21h mov ah,1 int 21h mov dl,al mov ah,2 add dl,20h int 21h mov cx,25 y: mov ah,2 dec dl int 21h loop y mov ah,4ch int 21h main endp nlcr proc mov ah,2 mov dl,13 int 21h mov dl,10 int 21h ret nlcr endp end start What is the Output screenshotsComputer Science Is it possible to convert this to java? #include <stdio.h> void printBinary(int n, int i) { // Prints the binary representation // of a number n up to i-bits. int k; for (k = i - 1; k >= 0; k--) { if ((n >> k) & 1) printf("1"); else printf("0"); } } typedef union { float f; struct { // Order is important. // Here the members of the union data structure // use the same memory (32 bits). // The ordering is taken // from the LSB to the MSB. unsigned int mantissa : 23; unsigned int exponent : 8; unsigned int sign : 1; } raw; } myfloat; // Function to convert real value // to IEEE floating point representation void printIEEE(myfloat var) { // Prints the IEEE 754 representation // of a float value (32 bits) printf("%d | ", var.raw.sign);…
- n C language, define the following variant of the Fibonacci sequence called Fib3 without recursion : fib3(0) = 0 fib3(1) = 1 fib3(2) = 2 fib3(n) = fib(n-1)+fib(n-2)+fib(n-3) for all n>=3 That is, the sequence is 0, 1, 2, 3, 6, 11, 20, 37, 68, 125, ... unsigned long fib3 (unsigned int n); Your function should work correctly for inputs up to n=60, and run under a second.Someone tries to fix the stack based buffer overflow problem as follows, is it secure now? why? Are there any other issues within the function's implementation below? Explain your reasoning. int bof(char *str, int size) { char *buffer = (char *) malloc(size); strcpy(buffer, str); return 1; }Consider there are random numbers and their size is not predictable initially. The requirement is to store them in a way that is efficient in the following means: the chosen data structure is memory efficient a lot of insertions and deletions are expected from the given positions a lot of insertions and deletions are expected based on noduplicate allowed rule a lot of insertions and deletions are expected from given positions’ successor/predecessor