What is the contents of the stack after executing the instruction marked by * for the second time .org Ox00 LDI R16, HIGH(RAMEND) OUT SPH, R16 LDI R16, LOW(RAMEND) OUT SPL, R16 LDI R17, 0 CALL L1 CALL L2 CALL L3 HERE: JMP HERE .org 0x100 L1: INC R17 CALL L2 INC R17 RET .org 0x200 L2: INC R17 * CALL L3 INC R17 RET .org 0x300 L3: INC R17 RET

What is the contents of the stack after executing the instruction marked by * for the second time .org Ox00 LDI R16, HIGH(RAMEND) OUT SPH, R16 LDI R16, LOW(RAMEND) OUT SPL, R16 LDI R17, 0 CALL L1 CALL L2 CALL L3 HERE: JMP HERE .org 0x100 L1: INC R17 CALL L2 INC R17 RET .org 0x200 L2: INC R17 * CALL L3 INC R17 RET .org 0x300 L3: INC R17 RET

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Generate a listing file for AddTwoSum.asm(in 3.4.3 of the text) and write a description of the machine code bytes generated for each instruction. You can write your descriptions directly over the .lst file. You might have to guess at some of the meanings of the byte values. ; AddTwoSum.asm - Chapter 3 example. .386.model flat,stdcall.stack 4096ExitProcess proto,dwExitCode:dword .datasum dword 0 .codemain proc mov eax,5 add eax,6 mov sum,eax invoke ExitProcess,0main endpend main
Below is a program block written in ARM Assembly. Since initially PC = 0x2000, Stack pointer sp = 0x400 (no data in the stack memory and shown next), what are the LR and SP values when PC = 0x2028 (when the corresponding row is executed)? A. LR = 0x2048,SP = 0x3F0 B. LR = 0x201C,SP = 0x3F4 C. LR = 0x202C,SP = 0x408 D. LR = 0x2008,SP = 0x3F8 E. LR = 0x201C,SP = 0x404
Considering the following contents of Stack Segment (SS) Register and Stack Pointer (SP) Register: SS = A5B0H, SP = 4DF0H (a) Calculate the values of Top of Stack (ToS) and Bottom of Stack (BoS)? (b) Consider the following operations on the stack: PUSH AX PUSH [CX] PUSH 10 POP [BX] POP AX What is the value of ToS after all these operations? Also, provide the value of ToS after each instruction.
Below is a program with ARM Assembly. PC = 0x2000, Stack pointer sp = 0x400 (no heap or memory = 0x2000), no x2028 can be read (when in the corresponding row) What is the SP value and what dataset is in the stack base address 0x3F8?
Write an Arm Assembly Program that does the following:•Stores on the stack a list of words of memory where the first element of the list is how manyremaining elements are in the list, and the rest of the elements in the list are initialized tosome random values.– Example:list: 6, -3, 4, 5, 9, 22, 99//stores a list of the 6 elements -3, 4, 5, 9, 22, 99•At the end of the program, register r0 should hold the sum of only the negative values in thearray (nonnegative elements are ignored).•Note that your program must work correctly even if the values stored in the list are changed.
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Here is a small snippet of code that saves $t0 $t1 and $t2 in order to stack ie first saves t0 then t1 and finally t2 what instruction should be put in the place of x y z X sw $t0, 8($sp) Y Z
Hi there, I'm looking for some help with this MIPS code. I'm trying to see why the code is sub-optimal and what a more optimised solution would be. The code is being generated to compute: i := i-1; move $t8,$s0PUSH $t8li $t9,1POP $t8sub $s0,$t8,$t9 Assumptions: - PUSH x pushes the content of register x to the top of the stack- POP x pops the stack and stores the top element in register x- Variable i is stored in register $s0
Copy the top 2 words from the stack into registers AX and CX respectively. Do this withoutchanging the stack pointer do not use POP instructions! Use BP as the base register. Howwill your program know what value to place in BP?To ensure that the stack contains some known values, place the following code at thebeginning of your program:mov dx, 1234Hpush dxmov dx, 0ABCDHpush dxSave the based.s source file as /home/username/project1/based.s
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Question 17 Question text What are the instruction needed if the Postfix Machine program detect an operand? -pop two items from stack -the expression is evaluated pushed the result onto the stack -push it onto a stack -print the top item from stack Question 18 Question text Why input string of the Postfix Machine need to be split into tokens? -Easier to split string into two sub strings -To split string into many single characters -To split string into a list of sub strings -To hold many types of data Question 19 Question text Two types of tokens that need to be identified by the Postfix Machine are operator and operand. -True -False Question 20 Question text What instructions needed if the Infix-Postfix Converter program detect the token is an operator? -Immediately output the token. -Pop all stack symbols until a symbol of lower precedence or a right-associative symbol of equal precedence appears.…