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What is the E value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e™ = PbSO4(s) + 2 H20() E° = 1.690 V %3D PbSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4¯(aq) EO = -0.356 V a. +2.046 V b.-2.046 V O c. +2.758 V O d. +1.334 V

What is the E value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e™ = PbSO4(s) + 2 H20() E° = 1.690 V %3D PbSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4¯(aq) EO = -0.356 V a. +2.046 V b.-2.046 V O c. +2.758 V O d. +1.334 V

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 24E: For each reaction listed, determine its standard cell potential at 25 C and whether the reaction is...
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What is the E value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e¯ = PbSO4(s) + 2 H20() E° = 1.690 V %3D PbSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4¯(aq) EO = -0.356 V a. +2.046 V b.-2.046 V O c. +2.758 V O d.+1.334 V
Transcribed Image Text:What is the E value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e¯ = PbSO4(s) + 2 H20() E° = 1.690 V %3D PbSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4¯(aq) EO = -0.356 V a. +2.046 V b.-2.046 V O c. +2.758 V O d.+1.334 V
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