What is the equation of a circle having (10,2) and (6,-4) as endpoints of its diameter? x² + y² 16x - 2y + 52 = 0 - x² + y²-16x + 2y + 52 = 0 Option 1 Option 2 x² + y² + 16x - 2y + 52 = 0 x² + y²-16x + 2y - 104 = 0 Option 3 Option 4

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