What is the equation of line tangent to y = sin z+1 at cos z the point (7, –1)? O y = nz – 1 O y =z- (7 + 1) O y = z - A O y == -*+1

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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What is the equation of line tangent to y =
sin z+1
at
cos E
the point (7, –1)?
O y = TZ – 1
O y = = – (a+ 1)
O y = 1 -T
O y = * – * +1
Transcribed Image Text:What is the equation of line tangent to y = sin z+1 at cos E the point (7, –1)? O y = TZ – 1 O y = = – (a+ 1) O y = 1 -T O y = * – * +1
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