What is the equation of the line tangent to the graph of y = (2x+3)/(3x-2) at the point (1,5)? 13x - y - 8 = 0 O 13x + y - 18 = 0 O x - 13y - 64 = 0 O x + 13y - 66 = 0

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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What is the equation of the line tangent to the graph of y = (2x+3)/(3x-2) at
the point (1,5)?
O 13x - y - 8 = 0
О 13х +у- 18 %3D 0
O x- 13y - 64 = 0
O x + 13y - 66 = 0
Transcribed Image Text:What is the equation of the line tangent to the graph of y = (2x+3)/(3x-2) at the point (1,5)? O 13x - y - 8 = 0 О 13х +у- 18 %3D 0 O x- 13y - 64 = 0 O x + 13y - 66 = 0
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