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Social ScienceWhat is the final concentration of HCl in a solution prepared by addition of 922.0 mL of 4.73 M HCl to 549.0 mL of 2.03 M HCl? Assume volumes are additive.
What is the final concentration of HCl in a solution prepared by addition of 922.0 mL of 4.73 M HCl to 549.0 mL of 2.03 M HCl? Assume volumes are additive.
Expert Answer
Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.
Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;
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Moles of solute Molarity volume of solution in L Mass of solute ing Molar mass of solute (g/mol) Moles
The molarity of mixture of two solutions can be calculated with the help of:
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м, xV, + M, х V, - м, х V, V2 M X 3
Given:
V1 = 922.0 mL
M1 = 4.73 M
V2 = 549.0 mL
M2 = 2.03 M
M3 = Need to calculate
V3= 92...
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