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- Consider a 1.000-L stock solution of 9.69 M Na3PO4. A 2.000-mL aliquot is taken from this stock solution and diluted to a final volume of 1.000 L. A 5.000-mL aliquot is then taken from this new solution and further diluted to make a new solution with a final volume of 750.0 mL. Calculate Na+ in the final solution.If a solution is made by adding 8g of (NH4)2SO4 to a 100 ml volumteric flask and enough water is added to bring the total volume to 100ml, what would the density of the solution be? This is a straightforward question but I just wanted some clarification. When we bring the total volume to 100ml, does that mean we added 100ml of water? Will the mass of the water be 100 g regardless of the amount of solute added?I need to make a solution containing 0.025 grams per liter. However, I do not want to weigh 0.025 grams and put this in one liter of solvent. I want to make a stock solution of 0.25 grams in 500 ml of solvent and take a unknown aliquot and dilute this in 500ml of solvent instead of 1000 ml of solvent. How do I calculate the volume of aliquot from the stock solution to achieve a final concentation of 0.025 grams per liter? What is the proper equation(s) required to figure out the proper aliquots required?
- A 25mL volumetric pipet is used to deliver a sample of the stock solution marked “0.6000M X2SO4” into a 100mL volumetric flask. Distilled water is added to the flask until it is about 3/4thfull, the solution is mixed well, then more water is added to fill it up to the calibration mark, then it is mixed again. Calculate the concentration of X+ion in the dilute solution made above.A chemist attempts to prepare some very pure crystals of borax by dissolving100g of Na2B4O7 in 200 grams of boiling water. He then cools the solution slowly until some borax crystallizes out. Calculate the grams of borax recovered in the crystals per 100 grams of initial solution (Na2B4O7 plus water), if the residual solution at 55oC after the crystals are removed contains 12.4% Na2B4O7.What is the percent yield or percent recovery of Na2B4O7. Show process diagram and solution.A chemist attempts to prepare some very pure crystals of borax by dissolving100g of Na2B4O7 in 200 grams of boiling water. He then cools the solution slowly until some borax crystallizes out. Calculate the grams of borax recovered in the crystals per 100 grams of initial solution (Na2B4O7 plus water), if the residual solution at 55oC after the crystals are removed contains 12.4% Na2B4O7.What is the percent yield or percent recovery of Na2B4O7.
- 1) How much total glucose is present in a 75 Kg female person? (a normal person (70 kg BW) has approximately 43L body fluid).2) Please express the normal salt (NaCl) concentration in body fluid into molarity (mM).3) Commercial fuming Sulphuric acid (Oleum-H2S2O6) is 99.9% solution. Please convert it into molarity.4) Find out the Volume (dm3) of product (gas) at RTP when 0.58 M, 150 mL NaOH (aq.) reacts with 350 mL, 0.25 NH4Cl.5) The above reaction has the product Ammonia, which when dissolved in 650 mL ethanol makes an alkaline ethanolic solution. Find its molarity (M).6) Calculate the adult dose as per the BW of the baby. (Child dose-50 mg and the BW of the baby is 48 lb (British pound) (1lb=0.453 Kg)Run 1 Run 2 Molarity of KMnO4 solution (M) from bottle 0.00101 0.00101 Initial reading of buret KMnO4 (mL) 0.62 11.35 Final reading of buret KMnO4 (mL) 11.33 21.70 Run 1 Run 2 Volume of KMnO4 solution (mL) Moles of MnO4- used for titration (mol) Moles of C2O42- in 100.0 mL of solution (mol) Molarity of C2O42- (M) Molarity of Cd2+ (M) Ksp of CdC2O4 Average Ksp of CdC2O4 Calculations: Moles of MnO4- used for titration of saturated solution CdC2O4 Moles of C2O42- in 100.0 mL of saturated solution of CdC2O4 Molarity of C2O42- in saturated solution of CdC2O4 Molarity of Cd2+ in saturated solution of CdC2O4 Solubility product, Ksp, of CdC2O4A solution is prepared by dissolving 155.0 mL of methanol (CH3OH, density = 0.791 g/mL) in 250 mL of water (density 1.00 g/mL) to give a final solution volume of 350.0 mL. Calculate the (a) molarity of the solution, (b) %wt/wt, (c) %wt/vol, (d) %vol/vol
- How many milligrams of solute are there in 100 uL of a 50mM NaCl solution (MW 58.44 g/mole)? Show your work and answer in milligrams.A solution was prepared by taking 4.00 mL of 0.520 M MgCl2 solution and diluting to 50.00 mL. What is the concentration in the resulting solution? Answer in correct significant figures.Volume of an unknown used was 30 mL, Initial Buret volume was 0 and the Final Buret volume was 8.5 mL. What is the molarity of the unknown solution if the Net volume of NaOH being used was 8.5 mL and Millimoles (mmoles) NaOH reacted was 0.791? Then, what is the Mass (g) of Acetic Acid in unknown sample and thr average percent (%) Acetic Acid? (assume density = 1g/mL)
