What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.90×1015Hz?Express your answer in joules to three significant figures. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays offrequency 1.90 × 1015 Hz ?Express your answer in joules to three significant figures.• View Available Hint(s)?a|X|х.10п– 19|KE = 9.24 • 10¯1JSubmitPrevious AnswersX Incorrect; Try Again; 4 attempts remaining Electrons are emitted from the surface of a metalwhen it's exposed to light. This is called thephotoelectric effect. Each metal has a certainthreshold frequency of light, below which nothinghappens. Right at this threshold frequency, anelectron is emitted. Above this frequency, theelectron is emitted and the extra energy istransferred to the electron.The equation for this phenomenon isΚΕhv-hvowhere KE is the kinetic energy of the emittedelectron, h = 6.63 × 10¬34 J. s is Planck'sconstant, v is the frequency of the light, and vo isthe threshold frequency of the metal.Also, since E = hv, the equation can also bewritten asKE= E – ¢where E is the energy of the light and ø is thebinding energy of the electron in the metal.

The emission of electrons from the surface of metals when light or any other radiation of suitable…

Answered: What is the kinetic energy of the…

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.90×1015Hz? Express your answer in joules to three significant figures.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter5: Electron Configurations And The Periodic Table

Section: Chapter Questions

Problem 34QRT: Spectroscopists have observed He+ in outer space. This ion is a one-electron species like a neutral...

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Question

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.90×10¹⁵Hz?

Express your answer in joules to three significant figures.

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of
frequency 1.90 × 1015 Hz ?
Express your answer in joules to three significant figures.
• View Available Hint(s)
?
a
|X|
х.10п
– 19|
KE = 9.24 • 10¯1
J
Submit
Previous Answers
X Incorrect; Try Again; 4 attempts remaining

Electrons are emitted from the surface of a metal
when it's exposed to light. This is called the
photoelectric effect. Each metal has a certain
threshold frequency of light, below which nothing
happens. Right at this threshold frequency, an
electron is emitted. Above this frequency, the
electron is emitted and the extra energy is
transferred to the electron.
The equation for this phenomenon is
ΚΕhv-hvo
where KE is the kinetic energy of the emitted
electron, h = 6.63 × 10¬34 J. s is Planck's
constant, v is the frequency of the light, and vo is
the threshold frequency of the metal.
Also, since E = hv, the equation can also be
written as
KE= E – ¢
where E is the energy of the light and ø is the
binding energy of the electron in the metal.

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