Question
Asked Feb 8, 2019
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What is the molality of a solution of 33g of propanol ( CH3CH2CH2OH) in 152 mL water, if the density of water is 1g/mL?

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Expert Answer

Step 1

molality is moles of solute dissolved per kg of solvent

molality = moles/kg of solvent

Step 2

moles = mass of solute (g)/molar mass of solute (g/mol)

Given here,

mass of propanol = 33 g

molar mass of propanol = 60.09 g/mol

volume of solvent (water) = 152 ml

density of water = 1 g/ml

So, mass of water = 152 ml x 1 g/ml = 152 g

                                                                              &nbs...

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