Question
Asked Oct 23, 2019

What is the molar solubility of PbI2 in 0.100 M NaI? Ksp PBI2+ 9.8 x 10-9.

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Step 1

The molar solubility of PbI2 in 0.100 M NaI is to be calculated. 

Ksp of PBI2 = + 9.8 x 10-9.

Step 2

Ksp is the product of the molar solubility of the ions in a saturated solution.

Where molar solubility is the moles of solute dissolved in one litre of its saturated solution.

 

Step 3

NaI and PbI2 has common ion – iodide ion.

The solution is of 0.100 M NaI which dissociates to give 0.100 M Na+ and 0.100 M I...

NaI (aq)Na* (aq) +I (aq)
0.100 mole of Nal yield 0.100 mole ofI
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NaI (aq)Na* (aq) +I (aq) 0.100 mole of Nal yield 0.100 mole ofI

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