What is the output generated by the following code: int x 4; for (int i = e; i >» -1 * x; i--) { for (int j- 0;j»i; j:) { cout s cout < "" 2020 il Select one: # #**##s O #.### O O Nono of tho othor options ******** *#**# # # # ##.
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- trace the following code and give the output. for (int a = 1; a <= 3; a++) for (int b = 1; b <= 3; b++) cout << a+b << endl;trace the following code and give the output. for (int i=1; i<=20; i++) cout << "? ";Consider the following code and write the output of this code? int **p; p = new int* [5];for (int i = 0; i < 5; i++) p[i] = new int[3]; for (int i = 1; i < 5; i++) for (int j = 0; j < 3; j++) p[i][j] = 2 * i + j; for (int i = 1; i < 5; i++) { for (int j = 0; j < 3; j++) cout << p[i][j] << " "; cout << endl;}
- What is the output of the following code segments (when run independently)? int [ ] myAry = {10,20,30,40,50}; for (int x=0; x<=myAry.length-1; x++ ) System.out.print(" " + myAry[x] ); note : a java codeQuestion 1 Work your way through the following code fragments. What would be printed? a) int i = -23; int * p = &i; printf("*p = %i\n", *p); b) int i; int * p = &i; printf("*p = %i\n", *p); c) int i = 48; int * p; printf("*p = %i\n", *p); d) int i = 10;int * p = &i;int j; j = ++*p; printf("j = %i\n", j);printf("i = %i\n", i); e) int i = 10, j = 20;int * p = &i;int * q = &j; *p = *q;printf("i = %i, j = %i\n", i, j);printf("*p = %i, *q = %i\n", *p, *q); i = 10; j = 20; p = q;printf("i = %i, j = %i\n", i, j);printf("*p = %i, *q = %i\n", *p, *q);What is the the output of the following code? int **p;p = new int* [5];for (int i = 0; i < 5; i++)p[i] = new int[3];for (int i = 1; i < 5; i++) for (int j = 0; j < 3; j++)p[i][j] = 2 * i + j;for (int i = 1; i < 5; i++){for (int j = 0; j < 3; j++)cout << p[i][j] << " ";cout << endl;}
- 1 int[] a = new int[n]; 2 a[0] = 0; a[1] = 1; 3 int x = 0; 4 for (int i = 2; i < n; i++) { 5 x = 3 * (i-1) * (i-1); 6 x += 3 * i - 2; 7 a[i] = a[i-1] + x; 8 } The code can be simplified by replacing lines 5, 6, 7 with a single line of code. Write the single line of code below:What does the following code? void xxxx(int arr[], int index[], int n){int temp[n]; for (int i=0; i<n; i++)temp[index[i]] = arr[i]; for (int i=0; i<n; i++){arr[i] = temp[i];index[i] = i;}}(JAVA)Consider this code: int m = 3; int n = -2; m = ++m * n--; What are the final values of m and n?
- In each of the following code snippets, data is copied from x to y. How many bytes of data arecopied? The answer should be a C expression.Example: int x[10], y[10];...for (int i=0; i<10; i++)x[i] = y[i];Answer: 10*sizeof(int)Example: int *x, *y; ...; y = x;Answer: sizeof(int*) (e) int x=10, y=x;(f) int x[10]; int *y = x;(g) int x[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};void f(int y[5]) { ... }int main() { f(x); }(h) int x[10], y[10];...memcpy(y, x, 5*sizeof(int));for (int i = 1; i <= 3; i++) { for (int j = 1; j <= 3; j++) { System.out.print((i * j) + " "); }1. What is the output of the following program segment: C++ int temp[5];for (int i = 0; i < 5; i++) temp[i] = 2 * i - 3; for (int i = 0; i < 5; i++) cout << temp[i] << " "; cout << endl;temp[0] = temp[4];temp[4] = temp[1];temp[2] = temp[3] + temp[0]; for (int i = 0; i < 5; i++) cout << temp[i] << " "; cout << endl;