What is the output? Image attached. A. 4-16-36-64 B. -416-3664 C. 4-1636-64 int[] myList = new int[}{ 2,4,6,8 }; for(int i = 8; i < myList.length; i++) { if( i % 2 == e) { myList[i] *= myList[i]; } else { myList[i] *= nyList[i] * -1; } %3D %3D
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- Draw the function ? = 1⁄(1 + ?2) on 2 dimensions X and Z by dividing the -2π to 2π range of x from steps of 0.1 with color blue and dash-dotted line. Imagine that the drawn line of z is a ‘thread’ which if we can copy it multiple times and those copies are kept in parallel to the first one over the direction of a 3rd axis we will generate a surface representing the same curve. a. Use meshgrid function on the x vector and save the result on xx. b. Using size function find the size of xx. c. How does dimensions of xx relate to dimensions of x? d. Using the knowledge of vector multiplication in Octave and using in-built generating functions and size functions, for a given vector v write a single argument function to generate its ‘meshgrid version’ and return it in the variable rep. Avoid using loops! Name your function replicate. (Note: Check if the result is identical to the meshgrid function’s output. Cross check with a small vector) ChatGPTSuppose that the virtual page reference stream contains repetitions of long sequences of page references followed occasionally by a random page reference. For example, the sequence: 0, 1, ... , 511, 431, 0, 1, ... , 511, 332, 0, 1, ... consists of repetitions of the sequence 0, 1, ... , 511 followed by a random reference to pages 431 and 332. (a) Why will the standard replacement algorithms (LRU, FIFO, clock) not be effective in handling this workload for a page allocation that is less than the sequence length? (b) If this program were allocated 500 page frames, describe a page replacement approach that would perform much better than the LRU, FIFO, or clock algorithms.Draw the Weighted Quick Union object on 0 through 10, that results from the following connectconnectcalls. Do not use path compression. Note that if we connect two sets of equal weight, by convention we make the set whose root has a smaller number the parent of the other. We use the convention that if an element is the root of the set, its array value is the weight of the set negated. connect(0, 1); connect(2, 3); connect(9, 5); connect(5, 7); connect(7, 1); connect(4, 2); connect(3, 1);
- It will simulate the diffusion of heatthrough a square metal plate. The plate starts off at 0 deg., but the 4 ×4 pixel square in the centeris kept at 100 deg.Now a cell in the interior has 4 neighbors: the upper, lower, left, and right neighbor. The updateformula for an interior point (other than the center square) is therefore given by:u′i,j = ui,j + k((ui,j+1 −ui,j ) + (ui,j−1 −ui,j ) + (ui−1,j −ui,j ) + (ui+1,j −ui,j ))= ui,j + k(ui,j+1 + ui,j−1 + ui−1,j + ui+1,j −4ui,j )The boundaries have to be updated separately using 8 different equations: 4 for each of the edges,and 4 for each corner. Here is the update formula for a cell on the top edge that is not on a corner:u′i,n−1 = ui,n−1 + k((ui,n−2 −ui,n−1) + (ui−1,n−1 −ui,n−1) + (ui+1,n−1 −ui,n−1))= ui,n−1 + k(ui,n−2 + ui−1,n−1 + ui+1,n−1 −3ui,n−1)Here is the update formula for a cell in the top left corner:u′0,n−1 = u0,n−1 + k((u0,n−2 −u0,n−1) + (u1,n−1 −u0,n−1))= u0,n−1 + k(u0,n−2 + u1,n−1 −2u0,n−1) Program:Create a new concrete class that implements MyMap using open addressing with linear probing. For simplicity, use f(key) = key % size as the hash function, where size is the hash-table size. Initially, the hash-table size is 4. The table size is doubled whenever the load factor exceeds the threshold (0.5). Test your new MyHashMap class using the code at https://liveexample.pearsoncmg.com/test/Exercise27_01.txt Class Name: Exercise27_01 If you get a logical or runtime error, please refer https://liveexample.pearsoncmg.com/faq.html MyHashMap.java located here https://liveexample.pearsoncmg.com/html/MyHashMap.html? MyMap.java located here https://liveexample.pearsoncmg.com/html/MyMap.html IMPORTANT Please do not take answers from Chegg or the rest of the internet, they are all wrong (I checked them). Please only provide a solution if you know the answer. I need to submit the code to Revel, I do not need the entire code, I need to submit the code enclosed between // BEGIN…Code Example 18-21. import tkinter as tk2. from tkinter import ttk3. class TipCalcFrame(ttk.Frame):4. def __init__(self, parent):5. ttk.Frame.__init__(self, parent, padding="20 20 20 20")6. self.pack()7. self.mealCost = tk.StringVar()8. self.tipPercent = tk.StringVar()9. self.tipAmount = tk.StringVar()10. ttk.Label(self, text="Cost of your meal:").grid( column=0, row=0, sticky=tk.E)11. ttk.Entry(self, width=30, textvariable=self.mealCost).grid( column=1, row=0)12. ttk.Label(self, text="Percent to leave as a tip:").grid( column=0, row=1, sticky=tk.E)13. ttk.Entry(self, width=30, textvariable=self.tipPercent).grid( column=1, row=1)14. ttk.Label(self, text="Tip amount:").grid( column=0, row=2, sticky=tk.E)15. ttk.Entry(self, width=30, textvariable=self.tipAmount,…
- Code Example 18-21. import tkinter as tk2. from tkinter import ttk3. class TipCalcFrame(ttk.Frame):4. def __init__(self, parent):5. ttk.Frame.__init__(self, parent, padding="20 20 20 20")6. self.pack()7. self.mealCost = tk.StringVar()8. self.tipPercent = tk.StringVar()9. self.tipAmount = tk.StringVar()10. ttk.Label(self, text="Cost of your meal:").grid( column=0, row=0, sticky=tk.E)11. ttk.Entry(self, width=30, textvariable=self.mealCost).grid( column=1, row=0)12. ttk.Label(self, text="Percent to leave as a tip:").grid( column=0, row=1, sticky=tk.E)13. ttk.Entry(self, width=30, textvariable=self.tipPercent).grid( column=1, row=1)14. ttk.Label(self, text="Tip amount:").grid( column=0, row=2, sticky=tk.E)15. ttk.Entry(self, width=30, textvariable=self.tipAmount,…Code Example 18-21. import tkinter as tk2. from tkinter import ttk3. class TipCalcFrame(ttk.Frame):4. def __init__(self, parent):5. ttk.Frame.__init__(self, parent, padding="20 20 20 20")6. self.pack()7. self.mealCost = tk.StringVar()8. self.tipPercent = tk.StringVar()9. self.tipAmount = tk.StringVar()10. ttk.Label(self, text="Cost of your meal:").grid( column=0, row=0, sticky=tk.E)11. ttk.Entry(self, width=30, textvariable=self.mealCost).grid( column=1, row=0)12. ttk.Label(self, text="Percent to leave as a tip:").grid( column=0, row=1, sticky=tk.E)13. ttk.Entry(self, width=30, textvariable=self.tipPercent).grid( column=1, row=1)14. ttk.Label(self, text="Tip amount:").grid( column=0, row=2, sticky=tk.E)15. ttk.Entry(self, width=30, textvariable=self.tipAmount,…How to do the kSum in O(1), i only can do it like public long ksum(int k) { long sum = 0; for(int i=0; i<k && i<ds.size(); i++) sum += ds.get(ds.size() - 1 - i); return sum; } The hint is Consider the data stream: 1 2 3 4 5Store this in a arraylist: [1,2,3,4,5]Now have a cumulative sums arraylist:data: [1sums = [1 data: [1, 2sums = [1, 3 data: [1,2,3sums: [1, 3, 6 data: [1, 2, 3, 4sums: [1, 3, 6, 10 data: [1, 2, 3, 4, 5]sums: [1, 3, 6, 10, 15] Now if in part1, calculate ksum(2):sums list: [1, 3, 6, 10, 15]ksum(2) = 9If you can correctly identify which values at which particular indices you subtract to get ksum(2) = 9 in this case, you have a O(1) solution for ksum, since with each addition and removal of an element from the raw data arraylist, you add and remove from the sums arraylist as well but i do not get it. Please give a code for example
- Can you write me a linked list function in COQ and prove that function in the COQ proof language make sure to use iris tactics following can be helpfull links for refrence materialshttps://gitlab.mpi-sws.org/iris/iris/-/blob/master/iris_heap_lang/notation.v?ref_type=headshttps://gitlab.mpi-sws.org/iris/iris/-/blob/master/docs/proof_mode.md?ref_type=headsCreate a newconcrete class that implements MyMap using open addressing with quadratic probing.For simplicity, use f(key) = key % size as the hash function, where sizeis the hash-table size. Initially, the hash-table size is 6. The table size is doubledwhenever the load factor exceeds the threshold (0.5).Suppose you have an object made up of two w-bit integers, x and y. Show why x+y does not make a good hash code for your object. Give an example of a large set of objects that would all have the same hash code. c++ and provide good comments.