What is the output of the following code? void funcA(int); int main() { int x = 4; funcA(x); cout << "x is " << x << endl; return 0; } void funcA( int n) { n += 3; }
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A: Hi there, Please find your solution below, I hope you would find my solution useful and helpful.…
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A: Q
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A: The code is now working I provide the code along with output and code screenshot
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A: As we know 3%2-1 =0 4%2 + 1 = 1
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A: Corrected code:Note: The modified statement is highlighted.#include <iostream>using namespace…
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A: The Answer is in Below Steps
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A: I give the code in C as per your requirement and also provide the output and code screenshot
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- In java Develop a function that takes two integers and returns the sum of the values from the first to the second (the two inputs may be in any order). Call the function at least twice with different arguments Develop a void function PrintLineOfChar that accepts a single character and an integer. The function prints a single line of the character repeated the integer number of times. Call the function at least twice with different arguments.Here thr____Calculator.java, to accept an expression as astring in which the operands and operator are separated by zero or more spaces.For example, 3+4 and 3 + 4 are acceptable expressions. Here is a sample run:++Create a program that takes two parameters called base and expo such that b ase is not zero and returns the value of baseexpo . Write a recursive function and call it power.
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