How many times "Testing" statement is printed in the following code? Public static void main(String[] args) { } int i = 20; do { i-=4; System.out.println("Testing\n"); } while (i > 5); Select one: a. 3 b. 2 c. 4 d. 1

Please explain this question void main() {int a =300; char *ptr = (char*) &a ; ptr ++; *ptr =2; printf("%d", a); }

#include <stdio.h> struct Single {     int num; };   void printSingle(int f) {     int binaryNum[33];     int i = 0;     while(f>0)     {         binaryNum[i] = f % 2;         f = f/2;         i++;     }     for (int j=i-1; j>= 0; j--)     {         printf("%d",binaryNum[j]);     } }   int main() {     struct Single single;     single.num = 33;     printf("Number: %d\n",single.num);     printSingle(single.num);     return 0; }

class Main {             // this function will return the number elements in the given range             public static int getCountInRange(int[] array, int lower, int upper)             {                         int count = 0; // to count the numbers                         // this loop will count the numbers in the range                         for (int i = 0; i < array.length; i++)                         {                     // if element is in the range                                     if (array[i] >= lower && array[i] <= upper)                                                 count++;                         }                                                 return count;             }               public static void main(String[] args)             {         // array         int array[] = {1,2,3,4,5,6,7,8,9,0};                         // ower and upper range                         int lower = 1, upper = 9;                         // throwing an exception…