What is the output of the following?int count = 3;while (--count > 0)cout << count << " ";
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A:
What is the output of the following?
int count = 3;
while (--count > 0)
cout << count << " ";
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- What is the output of the following program (when embedded in a complete program)? int count = 6; while (--count>0) cout << count << " ";int const MULTIPLIER = 5; is a valid way to declare a constant integer variable. Group of answer choices True False ------- Given the following code segment, what is output to the screen? int num1 = 6; int num2 = 4 * num1++; cout << "num1=" << num1 << " num2=" << num2; Group of answer choices num1=7 num2=24 num1=6 num2=24 num1=6 num2=28 Nothing, because the code does not compile.Assume that int a[ 2 ][ 2 ] = { { 1, 2 }, { 3, 4 } }; the value of a[ 1, 1 ] = ______;
- what will be the output? #include int main() {int i = 3; i++; printf ("%d", i); i--, printf("%d", i); return 0;}What happens if you multiply ptr by four? Assuming ptr is a reference to an int, the following happens:What is the output of the following code? for (int k = 2; k <= 10000; k = k * k)cout << k << " ";cout << endl;
- what will be the output? #include int main () {int i = 3; i++; print ("%d", i); i--; print ("%d", i); return 0;} a. 34, b. 33, c. 44, d. 43What happens if you multiply the number ptr by four? Assuming ptr is a reference to an int, the following happens:What is the printout of the following code segment? void fun(int *a) { *a *= 2; }int main() { int b = 3; fun(&b); cout << b; return 0; } A. 2 B. 3 C. 4 D. 6
- /*** calculate the product of numbers from start to end inclusive e.g.* calcProductOfRange(3, 6) = 3*4*5*6 = 360**/public static int calcProductOfRange(int start, int end) {What is the output of the following code?int[] values = new int[5];for (int count = 0; count < 5; count++)values[count] = count + 1;for (int count = 0; count < 5; count++)System.out.println(values[count]);What is the output of the following code? int *intArrayPtr;int *temp;intArrayPtr = new int[5];*intArrayPtr = 7;temp = intArrayPtr;for (int i = 1; i < 5; i++){intArrayPtr++;*intArrayPtr = *(intArrayPtr - 1) 1 2 * i;}intArrayPtr = temp;for (int i = 0; i < 5; i++){cout << *intArrayPtr << " ";intArrayPtr++;}cout << endl;