What is the output of the following code? int *intArrayPtr;int *temp;intArrayPtr = new int[5];*intArrayPtr = 7;temp = intArrayPtr;for (int i = 1; i < 5; i++){intArrayPtr++;*intArrayPtr = *(intArrayPtr - 1) 1 2 * i;}intArrayPtr = temp;for (int i = 0; i < 5; i++){cout << *intArrayPtr << " ";intArrayPtr++;}cout << endl;

Q1 #include <stdio.h>   int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key);   int *joinArray(int arrA[], int arrB[]) {     int j = 0;     if ((arrB[0] + arrB[4]) % 5 == 0)     {         arrB[0] = 0;         arrB[4] = 0;     }       for (int i = 0; i < 5; i++)     {         arrC[j++] = arrA[i];           if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1))         {             continue;         }         else             arrC[j++] = arrB[i];     }       for (int i = 0; i < j; i++)     {         int temp;         for (int k = i + 1; k < j; k++)         {             if (arrC[i] > arrC[k])             {                 temp = arrC[i];                 arrC[i] = arrC[k];                 arrC[k] = temp;             }         }     }     for (int i = 0; i < j; i++)     {         printf("%d ", arrC[i]);     }     return arrC; }   int bSearch(int arr[], int l, int h, int key) {     if (h >= l)     {         int mid = l + (h - l) / 2;           if…

6. Show the printout of the following code: public class ArraysBasic { public static void main(String[] args) { int A[] = {1, 2, 3}; } System.out.println("array A: " + A[0] +""+A[1]+""+ A[2]); System.out.println("array B: " + A[0] + " " + A[1] + " " + A[2]); zeroArray(A); A = new int[5]; System.out.println("array C: " + A[0] + " " + A[1] + " " + A[3] + " " + A[4]); } } public static void zeroArray(int[] list) { for (int j = 0; j < list.length; ++j) { list[j] = 99;

What happens when the ref or out keyword is used with an array parameter?

Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews O

AHPA #10:The Secure Array(use C programming)• A programmer that you work with, Peter, is a jerk.• He is responsible for an array [theArray] that is a key part of an importantprogram and he maintains a sum of the array values at location [0] in the array.• He won't give you access to this array; however, your boss has told you that youneed to get input from the user and then place it into the array.• Each evening Peter will scan the code and remove any illegal references to hisarray.• Using pointers, access Peter's array without him knowing it and place threevalues that you got from the user (101, 63, 21) at locations 3, 6, and 9.Recalculate the sum value and update it.   ( the output should be same as the picture)

//Assignment 06 */public static void main[](String[] args) {        String pass= "ICS 111";    System.out.printIn(valPassword(pass));}       /*   public static boolean valPassword(String password){    if(password.length() > 6)    {        if(checkPass(password)        {            return true;        }        else        {            return false;         }      }else       System.out.print("Too small");    return false;} public static boolean checkPass (String password){    boolean hasNum=false; boolean hasCap = false; boolean hasLow = false; char c;    for(int i = 0; i < password.length(); i++)    {        c = password.charAt(1);        if(Character.isDigit(c));        {            hasNum = true;        }        else if(Character.isUpperCase(c))        {            hasCap = true;        }        else if(Character.isLowerCase(c))        {            hasLow = true;        }    }      return true;    {        return false;    }         }

#include <stdio.h> struct Single {     int num; };   void printSingle(int f) {     int binaryNum[33];     int i = 0;     while(f>0)     {         binaryNum[i] = f % 2;         f = f/2;         i++;     }     for (int j=i-1; j>= 0; j--)     {         printf("%d",binaryNum[j]);     } }   int main() {     struct Single single;     single.num = 33;     printf("Number: %d\n",single.num);     printSingle(single.num);     return 0; }

In the C programming language, if all function prototypes are listed at the top of your code, outside and above all functions, you do not need to worry about the order of the function definitions within the code. True False

#include <stdio.h>   int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key);   int *joinArray(int arrA[], int arrB[]) {     int j = 0;     if ((arrB[0] + arrB[4]) % 5 == 0)     {         arrB[0] = 0;         arrB[4] = 0;     }       for (int i = 0; i < 5; i++)     {         arrC[j++] = arrA[i];           if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1))         {             continue;         }         else             arrC[j++] = arrB[i];     }       for (int i = 0; i < j; i++)     {         int temp;         for (int k = i + 1; k < j; k++)         {             if (arrC[i] > arrC[k])             {                 temp = arrC[i];                 arrC[i] = arrC[k];                 arrC[k] = temp;             }         }     }     for (int i = 0; i < j; i++)     {         printf("%d ", arrC[i]);     }     return arrC; }   int bSearch(int arr[], int l, int h, int key) {     if (h >= l)     {         int mid = l + (h - l) / 2;           if…