What is the output of the following * ?program
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A: START: LDA 2050HMOV B,ALDA 2051HCMP BJC OTHERSTA 2052HJMP ENDOTHER: STA 2053HEND: HLT
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Q: What is the output of the following ?program
A: Please find the answer below :
Q: what is the output of the following ?program
A: The answer of this question is as follows:
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- 1.The following is the C code that you need to implement for this lab: uint8_ t f(uint8_tn) return(n<2)?(n):(f(n-1)+f(n-2)); The main function can be assumed as follows: int main() uint8_ t x; x=f(???); return 0; Obviously, " ? ? ? " is representing a value used to test the algorithm! Is "f"recursive? a.No answer text provided. b.Yes c.no d.depends on whether it is in for main 2.First, make the code in the previous question an actual C program so that it can be compiled and it runs. Play with it so that you feel comfortable with the logic of the code. Then implement the code in TTPASM. Note that you need to preserve the actual C code structure, this means you cannot it into a non-recursive subroutine. Furthermoreall conventions discussed in class regarding subroutines must be followed. The idea is that I should be able to substitute f with my own code, and main should work. Or, I can substitute main with my own, and f should work. Attach the source code of your assembly…code in python (A) please Solve the so-called "Birthday Problem". Write a program that takes an integer ?N and uses the function np.random.randint (low = 0, high = N) from numpy to generate a random sequence of integers between 00 and ?−1N−1. Run experiments to validate the hypothesis that the number of integers generated until the first repeated value is approximately ?∗?2⎯⎯⎯⎯⎯⎯⎯√π∗N2. a) Write a function birthday(N) that returns the number of values generated until a value is repeated as a function of the range of possible values ?N (from 00 to ?−1N−1); b) Write a function birthday_sim(N) that repeats birthday(N) a total of n_sim = 20000 times and returns the average of all the numbers generated; c) Show on one plot that as ?N increases (with a doubling experiment), from ?=2N=2 to ?=1000N=1000, the value of birthday_sim(N) approaches ?∗?2⎯⎯⎯⎯⎯⎯⎯√π∗N2.Consider the following recursive function:void recEx11(int x){if (x > 0)if (x % 2 == 0){recEx11((x - 3) / 2);cout << x << " ";}else{recEx11((x - 4) / 2);cout << x << " ";}}What is the output of the following statements? a. recEx11(28); b. recEx11(148); c. recEx11(98); d. recEx11(-30)
- Consider the following recursive function:void recFun(int u){if (u == 0)cout << "Zero! ";else{cout << "Negative ";recFun(u + 1);}}What is the output, if any, of the following statements? a. recFun(8); b. recFun(0); c. recFun(-2);1. The following statements shown below will result in the printing of: for (i= 3; i < 15; i += 3) { printf ("%d ", i); ++i; } 2. Complete the following code segments below to display this output. Replace ??? with your answer. 11111 2222 333 44 5 for (int j = 1; j = j; k--) { ???; } printf("\n"); } 3. How many times does the program below prints an *? for (int i = 5; iConvert the following code into descriptive code, and verify using White Box Testing. int a[10]={23, 45, 10, 0, 98, 36, 2, 56, 34, 12}; for (int i=0; i a[j+1]) swap(&a[j], &a[j+1]); end-if end-for end-for
- Consider the following function: int secret(int m, int n) { int temp = n; for (int i = 1; i < abs(m); i++) temp = temp + n; if (m < 0) temp = -temp; return temp; } What is the output of the following C++ statements? i.cout << secret(5, 4) << endl; ii.cout << secret(-3, 20) << endl;- c program only Hi! Could you help me? I think something is wrong with my code but I couldn't figure out what. Also, please help me fix the `factorial` function, for it should apply recursion. Thanks! #include<stdio.h> int factorial(int n); int main(void) { int n; printf("Enter n: "); scanf("%d", &n); printf("Factorial of %d is %d", n, factorial(n)); return 0;} int factorial(int n) { if(n <= 1) { return 0; }else{ return factorial(n-1)*n; }} You can see below the attached pic of how the output should beComplete the program 'Bcast-Reduce-Assignment.c' (Refer to 'Bcast-Reduce-Example.c') to make the program have the output as follows if we run the program using 2 processes. The input sequence is: 0 1 2 3 The output sequence is: 0 2 6 12 The code below must be used, please #include <stdio.h>#include <stdlib.h>#include <mpi.h> int main(void) { int my_rank, comm_sz; int i; int Count = 4; int Number[4]; int Result[4]; MPI_Init(NULL, NULL); MPI_Comm_size(MPI_COMM_WORLD, &comm_sz); MPI_Comm_rank(MPI_COMM_WORLD, &my_rank); if(my_rank == 0) { printf("The input sequence is: \n"); for (i = 0; i < Count; i++) { Number[i] = i; printf("%d ", Number[i]); } printf("\n"); } // Process 0 sends data to all of the processes MPI_Bcast(Number, Count, MPI_INT, 0, MPI_COMM_WORLD); for (i = 0; i < Count; i++)…
- 1) #include #include int power(int, int); int main(void) { int x, n; printf("Enter a number and powerto raise it to: "); scanf_s("%d %d", &x, &n); printf("Result: %d\n", power(n, x)); return 0; } int power(int x, int n) { int m; if (n == 0) return 1; if (n % 2 == 0) { m = power(x, n / 2); return m * m; } else return x * power(x, n - 1); } 2) #include int hcf(int n1, int n2); int main() { int n1, n2; printf("Enter any two positive integers: "); scanf("%d %d", &n1, &n2); printf("Greatest Common Divisor of %d and %d is %d.", n1, n2, hcf(n1,n2)); return 0; } int hcf(int n1, int n2) { if (n2 != 0) return hcf(n2, n1%n2); else return n1; } 3) #include int main() { int array[], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) {…In each of the following code snippets, data is copied from x to y. How many bytes of data arecopied? The answer should be a C expression.Example: int x[10], y[10];...for (int i=0; i<10; i++)x[i] = y[i];Answer: 10*sizeof(int)Example: int *x, *y; ...; y = x;Answer: sizeof(int*) (e) int x=10, y=x;(f) int x[10]; int *y = x;(g) int x[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};void f(int y[5]) { ... }int main() { f(x); }(h) int x[10], y[10];...memcpy(y, x, 5*sizeof(int));trace the following code and give the output. for (int a = 1; a <= 3; a++) for (int b = 1; b <= 3; b++) cout << a+b << endl;