What is the pebble's moment of inertia with respect to the wheel's axis of rotation? Att = 3.70 [s], what is the pebble's rotational kinetic energy?
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- A disk 8.00 cm in radius rotates at a constant rate of 1200 rev/min about its central axis. Determine (a) its angular speed in radians per second, (b) the tangential speed at a point 3.00 cm from its center, (c) the radial acceleration of a point on the rim, and (d) the total distance a point on the rim moves in 2.00 s.A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of 0.700 m/s in 1.75 s. At t = 1.25 s, find the magnitude and direction of (a) the radial acceleration, (b) the tangential acceleration, and (c) the total acceleration of the point.The propeller of an aircraft accelerates from rest with an angular acceleration = 4t + 6, where is in rad/s2 and t isin seconds. What is the angle in radians through which thepropeller rotates from t = 1.00 s to t = 6.00 s?
- Jeff, running outside to play, pushes on a swinging door, causing its motion to be briefly described by = t2 + 0.800 t + 2.00,where t is in seconds and is in radians. At t = 0 and at t = 1.50s, what are the a. angular position, b. angular speed, and c. angularacceleration of the door?During a certain time interval, the angular position of a swinging door is described by = 5.00 + 10.0t + 2.00t2, where is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0 and (b) at t = 3.00 s.In testing an automobile tire for proper alignment, a technicianmarks a spot on the tire 0.200 m from the center. He then mountsthe tire in a vertical plane and notes that the radius vector to thespot is at an angle of 35.0 with the horizontal. Starting from rest,the tire is spun rapidly with a constant angular acceleration of 3.00 rad/s2. a. What is the angular speed of the wheel after 4.00 s? b. What is the tangential speed of the spot after 4.00 s? c. What is the magnitude of the total accleration of the spot after 4.00 s?" d. What is the angular position of the spot after 4.00 s?
- Why is the following situation impossible? Starting from rest, a disk rotates around a fixed axis through an angle of 50.0 rad in a time interval of 10.0 s. The angular acceleration of the disk is constant during the entire motion, and its final angular speed is 8.00 rad/s.A wheel 1.65 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 4.25 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s, find the following. What is the angular position of point P?An flywheel has an initial angular velocity of 10.1 Rad/s in the clockwise direction. If the flywheel undergoes uniform angular acceleration of +4.28 rad/s2 for 6.04 seconds, what is the angular velocity (magnitude and direction) after the period of acceleration? A. 15.8 rad/s (counterclockwise) B. 21.5 rad/s (clockwise) C. 33.6 rad/s (counterclockwise) D. 40.5 rad/s (clockwise) what is the angular displacement ∆θ (magnitude and direction) during the period of angular acceleration? A. 17.1 rad (clockwise)B. 17.1 rad (counterclockwise) C. 32.4 rad (clockwise)D. 32.4 rad (counterclockwise)
- A Ferris wheel with radius 14.8 m and initial angular speed 0.18 rad/s starts speeding up with constant angular acceleration 0.28 rad/s2. The magnitude of the resultant (total) acceleration of a point on the edge of the wheel 1.4 s after it starts speeding up isA cylinder rotating about its axis with a constant angular acceleration of 1.4 rad/s2 starts from rest at t = 0. At the instant when it has turned through 0.30 radian, what is the magnitude of the total linear acceleration of a point on the rim (radius = 15 cm)? Question 15 options: 0.24 m/s2 0.32 m/s2 0.29 m/s2 0.19 m/s2 0.26 m/s2An electric motor rotating a workshop grinding wheelat 1.00 x 10^2 rev/min is switched off. Assume the wheelhas a constant negative angular acceleration of magni-tude 2.00 rad/s^2. (a) How long does it take the grindingwheel to stop? Answer 5.24 s (b) Through how many radians has thewheel turned during the time interval found in part (a)? Answer 27.4 rad