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- Determine the magnitude of the y-component of force Q (N) if P=108.8 N, Q = 72.5 N , θ= 42.25° and α = 43.45°. Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the y-component.5m 4m 3 m B. Figure 2-2Given are the three forces F, = (2.27 + 2.2)N, F, = (2.27 - 2.2)N, and F3 = (-2.27 + 2.2) N. Which of the following vectors is net 1 Select one: Oa. R= (-2.2î+2.2) N Ob. R= (2.2î+2.2) N Oc. Ř= (6.6 7+ - 2.2)N Od. R= (2.2î+6.6 ) N Oe. Ř= (2.2 î+2.2) N
- Vector F₁ = 625 N makes an angle of 2700 when rotated counterclockwise from the +x axis. Vector F2 = 875 N makes a 1200 angle from Vector F₁ when rotated counterclockwise. What is the magnitude a vector needed to balance the two forces? O 680.6 N O86.2 N -980.6 N O-670.6 N O980.6 N 78.2 N O 580.6 N 780.6 NDetermine the magnitude of the x- component of force Q (in N) if P=96.4 N, Q = 55.2 N , 0= 55.53° and a = 49.46°.Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the x-component. Use R if to the right, L if to the left, U if upward or D if downward. y PProblem 1: For the force system shown, a fifth force F must be added so that the resultant of the five forces will be a 450 N force directed from B to D. What is the magnitude of the fifth force F? * D 90 N 220 N B 180 N А 220 N 100 mm 100 mm 48.19 N 56.32 N 164.162 N 441.403 N Other:
- F = (-30i + 60j + 60k )kN %3D Forces are concurrent at point O. Determine the magnitude of the resultant of the three vectors. a 71.5 kN b 187 kN F, = (60i – 20j+ 15k )kN c 116 kN d 83.7 kN Determine the angle between F, andF,. F, = (20j – 25k)kN X а 111° b 132° c 69.0° d 21.0° Select the expression that denotes a unit vector in the direction and sense of F,. a 0.625j -0.781k b 0.625i -0.781j c -0.625 j –0.781k d 0.625i +0.781jThe resultant of the concurrent forces has a magnitude of 1000 N passing through points (x₁ = 0, y₁ = 0, z₁ = 0) and (x₂ = 2, y₂ = 3, z₂ = 4). 1. Compute the x- component of the resultant force. a. 371.1 N b. 392.3 N c. 422.6 N d. 245.9 N 2. Compute the y – component of the resultant force. a. 512.9 N b. 557.1 N c. 435.8 N d. 634.7 N 3. Compute the z – component of the resultant force. a. 632.7 N b. 642.8 N c. 742.1 N d. 791.3 NFind the magnitude (in N/m) and direction (in degrees counterclockwise from the +x-axis) of the force that each wire experiences in the figure by using vector addition. (Assume that the +x-axis is to the right and the +y-axis is up along the page.) 6.50 A X. 19.5 A 45.5 A +13.0 cm- Top wire magnitude 0.000577 N/m direction 103 ° counterclockwise from the +x-axis Bottom left wire magnitude 0.00127 N/m direction 306 ° counterclockwise from the +x-axis Bottom right wire magnitude 0.00119 N/m direction 254 ° counterclockwise from the +x-axis 13.0 cm- -13.0 cm-
- Particle A lies on the x-y plane and is acted on by the three forces shown. Find the resultant of the three forces. 4.5m 2.1m A 1400 N 900N 1.8m 1000N 0,6m 18m 1.2m /CDetermine the magnitude of the resultant force (in N) of the coplanar force system shown in the figure below where the horizontal force P = 244 N and the couple M = 635 Nm. M N m A 150 N 300 mm 50 mm 400 mm 90N e to searchQuestion Completion Status: Vector F1 = 625 N makes an angle of 2700 when rotated counterclockwise from the +x axis. Vector F2 = 875 N makes a 1200 angle from Vector F1 when rotated counterclockwise. What is the magnitude a vector needed to balance the two forces? O 580.6 N O-980.6 N O 980.6 N O 780.6 N O 78.2 N 680.6 N O-670.6 N O 86.2 N