Part CWhat is the tangential speed of a point on the rim of the turntable at t= 0,207 s?Express your answer in meters per second.V=1.11 m/sPrevious AnswersCorrectPart DWhat is the magnitude of the resultant acceleration of a point on the rim at t= 0.207 s?Express your answer in meters per second squared.阳AE4a=7.95m/sSubmitPrevious Anywers Request Answerx Incorrect; Try Again; One attempt remaining An electric turntable 0.740 m in diameter is rotating about a fixed axis with an initial angular velocity of0.290 rev/s and a constant angular acceleration of 0.909 rev/sPart ACompute the angular velocity of the turntable after 0.207 sExpress your answer in revolutions per second.W= 0473 rev/sPrevious AnsWersCorrectPart BThrough how many revolutions has the turntable spun in this time interval?Express your answer in revolutions.N= 795-102 rev

Given data: d=0.74 mωi=0.29 rev/sα=0.909 rev/s2 Need to determine the angular, tangential velocity…

Answered: What is the tangential speed of a point…

What is the tangential speed of a point on the rim of the turntable at t =0,207 s? Express your answer in meters per second. V= 1.11 m/s Previous Anawers v Correct

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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