What is value in the variable x after the following code run? n=length(x); while n>1 x = x(1:2:end); n = length(x); end OA, the last value in the original vector x OB, the first value of the original vector OC, an empty vector. D. the size of the original vector x
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- Modify from the code below, add an additional input from the use input to get how many random integers to create. Use a vector<int> instead of an int array to store the random integers. Function prototypes: void showValues(const vector<int>&); void fillVector(vector<int>&, int, int); int maximum(const vector<int>&); int minimum(const vector<int>&); double average(const vector<int>&); bool searchValue(const vector<int>&, int); Code: #include <iostream>#include <iomanip>#include <cstdlib>#include <ctime>using namespace std; // Function prototypevoid showValues(const int[], int); void fillArray(int[], int, int, int); int maximum(const int[], int); int minimum(const int[], int); double average(const int[], int); int main(){const int ARRAY_SIZE = 10;int numbers[ARRAY_SIZE];srand(time(0));int low = 0, high = 1;cout << "**This program will generate 10 random integers between [low] and…We can dynamically resize vectors so that they may grow and shrink. While this is very convenient, it is inefficient. It is best to know the number of elements that you need for your vector when you create it. However, you might come across a situation someday where you do not know the number of elements in advance and need to implement a dynamic vector. Rewrite the following program so that the user can enter any number of purchases, instead of just 10 purchases. Output the total of all purchases. Hint: us do while loop with your vector.. #include <vector> #include <iostream> using namespace std; int main() { vector<double> purchases(10); for (int i = 0; i < 10; i++) { cout << "Enter a purchase amount"; cin >> purchases[i]; } return (0); }Write a program that first gets a list of integers from input and puts them into a vector. The input begins with an integer indicating the number of integers that follow. Then, get the last value from the input, which indicates a filtering threshold. Output all integers less than or equal to that last threshold value separated by a comma and space. Ex: If the input is: 5 50 60 140 200 75 100 the output is: 50, 60, 75 The 5 indicates that there are five integers in the list, namely 50, 60, 140, 200, and 75. The 100 indicates that the program should output all integers less than or equal to 100, so the program outputs 50, 60, and 75. Such functionality is common on sites like Amazon, where a user can filter results.
- Define an integer vector and ask the user to give you values for the vector. because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). thenGiven two arrays A and B of equal size N, the task is to find a vector containing only those elements which belong to exactly one array - either A or B - but not both. That is, if some element x appears in both A and B it should not be included in the output vector. Complete the implementation of "getVector(vector<ll>A, vector<ll>B, int N)" function. Example: Input: 1 3 5 7 1 3 2 4 6 7 8 Output: 3 5 1 3 2 4 6 8 The driver codes are attached in the images below. DO NOT CHANGE THE PROVIDED DRIVER CODES AT ALL, LEAVE THEM EXACTLY THE SAME. ONLY ADD CODE TO THE "getVector(vector<ll>A, vector<ll>B, int N)" FUNCTIONWrite a function that accepts a number, N, and a vector of numbers, V. The function will return two vectors which will make up any pairs of numbers in the vector that add together to be N. Do this with nested loops so the the inner loop will search the vector for the number N-V(n) == V(m). n and m are indices in the vector of numbers. Example A = [1,2,3,4,5,6, 7] Google(5, A) Return [1,2,3,4] and [4,3,2,1] being the pairs that sum to 5. Notice that each pair appears twice. Try to write code that does not do this.
- Assume you have a non-empty vector vec in your Matlab workspace. Will the following command: >> length(vec(vec == max(vec))) count all elements in vec with values equal to the maximum value in vector vec? Yes NoWhich shows valid accesses for an array a and vector v, each with 10 elements? In other words, this question is asking what is the proper syntax for accessing the array and vector. a. array: a[7] vector: v.at(5) b. array: a.at(5) vector: v[9] c. array: a.at(5) vector: v[5] d. array: a[1] vector v.at[4] Coding is in C++.Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shown locations. Use Vector ADT's erase() and insert() only, and remember that the first argument of those functions is special, involving an iterator and not just an integer. Sample output of below program with input 33 200 10: #include <iostream>#include <vector>using namespace std; void PrintVectors(vector<int> numsList) {unsigned int i; for (i = 0; i < numsList.size(); ++i) {cout << numsList.at(i) << " ";}cout << endl;} int main() {vector<int> numsList;int userInput;int i; for (i = 0; i < 3; ++i) {cin >> userInput;numsList.push_back(userInput);} /* Your solution goes here */ PrintVectors(numsList); return 0;} Please help me with this problem using c++.
- 6) While there is a built-in pop_back() method for vectors, there is no built-in pop_front method. Suppose a program needs a pop_front() method that will remove the first element from the vector. For example if the original vector is [1, 2, 3, 4, 5], then after passing in this vector to pop_front() the new resulting vector will be [2, 3, 4, 5]. Which of the options below is the correct implementation of pop_front()? Group of answer choices D-) void pop_front(vector<int> &v){ for(int i=0; i<(v.size()-1); i++)v[i+1] = v[i]; v.pop_back(); } C-) void pop_front(vector<int> &v){ for(int i=0; i<(v.size()-1); i++)v[i] = v[i+1]; v.pop_back(); } B-) void pop_front(vector<int> &v){ for(int i=0; i<v.size(); i++)v[i+1] = v[i]; v.pop_back(); } A-) void pop_front(vector<int> &v){ for(int i=0; i<v.size(); i++)v[i] = v[i+1]; v.pop_back(); } 7) Suppose a program has the following vector: [99, 23, 55, 71, 87, 64, 35, 42] The goal is to…is there another way without using vector?Write code for determining the index of a value in an OrderedVector. Be aware that if the value is not in the Vector, the routine returns the ideal location to insert the value. This may be a location that is outside the Vector(use java)