What mass of precipitate (in g) is formed when 20.5 mL of 0.700 MZn(NO:)2 reacts with 18.5 mL of 0.700 M NaOH in the followingchemical reaction?Zn(NO:)>(aq) + 2 NaOH(aq) → Zn(OH)>(s) + 2 NaNO:(aq)

We have to find out the limiting reagent initially. After finding out the limiting reagent we can…

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Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter4: Chemical Reactions In Solution

Section: Chapter Questions

Problem 4.120QE

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What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO:)2 reacts with 18.5 mL of 0.700 M NaOH in the following chemical reaction? Zn(NO:)>(aq) + 2 NaOH(aq) → Zn(OH)>(s) + 2 NaNO:(aq)