What value did you find for Letter P? 38 x 1.25 = 47.5 + 38 + 32 = 117.5 Amps 40 x 1.25 = 50 + 40 + 34 = 124 Amps 38 x 1.25 = 47.5 + 40 + 34 = 121.5 Amps 40 x 1.25 = 50 + 38 + 32 = 120 Amps
What value did you find for Letter P? 38 x 1.25 = 47.5 + 38 + 32 = 117.5 Amps 40 x 1.25 = 50 + 40 + 34 = 124 Amps 38 x 1.25 = 47.5 + 40 + 34 = 121.5 Amps 40 x 1.25 = 50 + 38 + 32 = 120 Amps
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter34: Motor Installation
Section: Chapter Questions
Problem 6PP: A 350-HP squirrel-cage induction motor is connected to a 480-volts three-phase feeder. The nameplate...
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What value did you find for Letter P?
38 x 1.25 = 47.5 + 38 + 32 = 117.5 Amps
40 x 1.25 = 50 + 40 + 34 = 124 Amps
38 x 1.25 = 47.5 + 40 + 34 = 121.5 Amps
40 x 1.25 = 50 + 38 + 32 = 120 Amps
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