What volume (in mL) of 0.300 M HCl would be required to completely react with 4.85 g of Al in the following chemical reaction? 2 Al(s) + 6 HCl(aq) → 2 AlCl₃ (aq) + 3 H₂ (g)

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter5: Gases, Liquids, And Solids
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What volume (in mL) of 0.300 M HCl would be required to completely react with 4.85 g of Al in the following chemical reaction? 2 Al(s) + 6 HCl(aq) → 2 AlCl₃ (aq) + 3 H₂ (g)
900G
A FA
зво м
я
в на за
6
4.05.
н
5388
, говоры H2
к
4.869
Imol Al
27а ал
да
" Х
1 mnd H₂
Да Н2
58,84 а на 11 тов
д
2 A1 C1₂ (aq)
З то на
ты А
На на
2 mol Al 1 mol H₂
на
знаку
-
Ce mol
Се тов на замід
на
molth t I mol Hel
на
19 на взы по нау
g
+3
()
lauc
193
20 9чен дінг
58.74
д
HCL
1000 не
100₁
384
196155 м
S
Ґ
Transcribed Image Text:900G A FA зво м я в на за 6 4.05. н 5388 , говоры H2 к 4.869 Imol Al 27а ал да " Х 1 mnd H₂ Да Н2 58,84 а на 11 тов д 2 A1 C1₂ (aq) З то на ты А На на 2 mol Al 1 mol H₂ на знаку - Ce mol Се тов на замід на molth t I mol Hel на 19 на взы по нау g +3 () lauc 193 20 9чен дінг 58.74 д HCL 1000 не 100₁ 384 196155 м S Ґ
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