What will be output to the screen when the following code is executed:
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A: I have answered the question in step 2.
What will be output to the screen when the following code is executed:
def PrintMe(x):
try:
return s * 5
except:
print("Error has occured")
finally:
print("Doing some cleanup")
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- What will be output to the screen when the following code is executed:def PrintMe(x): try: return s * 5 except: print("Error has occured") finally: print("Doing some cleanup")message = "HUE stands for Hadoop User Experience"print(PrintMe(message))What is the printout of the following code? x = 1 def f1(): x=3 print(x) f1() print(x)What is the value of x after the following code executes? int x=10; if(x++ >10) { x =13; } a. 10 b.9 c.13 d.11
- What would happen if you tried to execute the program after adding the following code before “return 0;” How could you fix it? Please describe it by words. Int*v=&t; Printf(“%d\n”,*v); Int*vThis code got error when i m trying to execute it.What is the output of the following code? def main(): x = do_something(3) y = do_something(x) print(x + y) def do_something(a): x = a - 1 b = a * 2 return b main()
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- Does the following code cause a memory leak?int* pValue = new int;*pValue = 45;pValue = new int;delete pValue; options: True False4. A) What will be the value of x after the following code is executed? int x, y = 4, z = 6; x = (y++) * (++z); B) Suppose a = 1. What is the value of a after the following code executes? Show the procedure to reach your answer if(a > 0) { switch(a) { case 1: a = a + 3; case 3: a++; case 6: a = a * 2; break; case 8: a--; break; default a++; } else a = a + 2; C) What would be the value of x after the following statements were executed? int x = 10; switch (x) { case 10: x += 15; case 12: x -= 5; break; default: x *= 3; }If you forget to declare the variable i in the following, what kind error will be raised? c++ while (i <= 9) cout << "hi"; A. a compilation error B. a runtime error C. a logic error D. no error