Find out (add code to print out) the address of the variable x in foo1, and the variable y in foo2. What do you notice? Can you explain this? */

Why am I getting errors?  Says "Index 0 out of bounds for length 0" I didn't specify when I asked this question last time, the program needs: write a program that takes two double command line arguments representing the sides of a rectangle. The program should then call a void function that reports the area of the rectangle accurate to three decimal places public static void main(String[] args) {        System.out.println("Enter length and width of rectangle");                for (int i=0; i < args.length; i++)        {            System.out.println(args[i]);        }                        Double area= Double.parseDouble (args[0]) * Double.parseDouble (args[1]);        System.out.println(" Area of rectangle is :" + String.format("%.3f", area));    } }

Hello, I have an assignment in the python program.  Professor gives me a text like this: January.txt 217283921200.5619.18,29.15,78.75,212.10100,20,410.29 The first line is an account number, the second line is the beginning balance, the third line is withdrawn and the last line is deposits. How can I separate every single line to read them. Can I use the loop function? Below is the assignment direction. Thank you very much ___________________________________________________________ Complete the following program: a) Read in and store the data from the file called “January.txt”. This file includes the customer’s account number, beginning balance, withdrawals, and deposits. (In that order) Note: Make sure you look at the file before you begin the project! b) Prompt the user for his/her name and age. c) Convert the customer’s name to a username that consists of the first letter of the first name, the first 5 digits of last name, and the customer’s age.(All letters should be lowercase)…

What is the value of the variable ss after the following code is executed? int x[ 7 ] = (5,10,3,0,-10, 4); int ss=0; for (int i=1;i<=6; i++) { ss+=x[i]; cout<