What will be the output of the following program in C++? #include using namespace std; class Test { static int x; public: Test() { x++; } static int getX() {return x;} }; int Test::x = 0; int main() { cout << Test::getX() << " "; Test t[5]; cout << Test::getX(); }
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What will be the output of the following program in C++?
#include <iostream>
using namespace std;
class Test
{
static int x;
public:
Test() { x++; }
static int getX() {return x;}
};
int Test::x = 0;
int main()
{
cout << Test::getX() << " ";
Test t[5];
cout << Test::getX();
}
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- What is the output of the following C++ code? #include <iostream> using namespace std; class BaseClass { protected: int i; public: BaseClass(int x) { i = x; } ~BaseClass() { } }; class DerivedClass: public BaseClass { int j; public: DerivedClass(int x, int y): BaseClass(y) { j = x; } ~DerivedClass() { } void show() { cout << i << " " << j << endl; } }; int main() { DerivedClass ob(3, 4); ob.show(); return 0; }What will be the evaluation results of each of the following expressionshown by GHCi ? Briefly explain. HASKELL a. > [(x,y) | x <- [1,2], y <- [4,5]]b. > [(y,x) | x <- [1,2], y <- [4,5]]This is C++. Please explain in details so I can understand the questions.What is the output of the following C++ program? #include <iostream>#include <string>using namespace std;class baseClass{public:void print() const;baseClass(string s = " ", int a = 0);//Postcondition: str = s; x = a;protected:int x;private:string str;};class derivedClass: public baseClass{public:void print() const;derivedClass(string s = "", int a = 0, int b = 0);//Postcondition: str = s; x = a; y = b;private:int y;};int main(){baseClass baseObject("This is the base class", 2);derivedClass derivedObject("DDDDDD", 3, 7);baseObject.print();derivedObject.print();system("pause");return 0;}void baseClass::print() const{cout << x << " " << str << endl;}baseClass::baseClass(string s, int a){str = s;x = a;}void derivedClass::print() const{cout << "Derived class: " << y << endl;baseClass::print();}derivedClass::derivedClass(string s, int a, int b) :baseClass("Hello…
- Consider the following program in C-like syntax:void f1();void f2();int main(){int x, y;...}int f1()int a, b, x;...}int f2(){int b, c, x, y;...} If the programming language uses dynamic scoping, what are the variables that arevisible in the last function in the following call sequences? Give not only the names ofthe variables, but also where they are declared.(a) main → f1 → f2(b) main → f2 → f1What will be the output of the following program in C++? #include <iostream>using namespace std;class Test{static int x;public:Test() { x++; }static int getX() {return x;}};int Test::x = 0;int main(){cout << Test::getX() << " ";Test t[5];cout << Test::getX();}What is the output of the following C++ program? #include <iostream> #include <string> using namespace std; class baseClass { public: void print() const; baseClass(string s = " ", int a = 0); //Postcondition: str = s; x = a; protected: int x; private: string str; }; class derivedClass: public baseClass { public: void print() const; derivedClass(string s = "", int a = 0, int b = 0); //Postcondition: str = s; x = a; y = b; private: int y; }; int main() { baseClass baseObject("This is the base class", 2); derivedClass derivedObject("DDDDDD", 3, 7); baseObject.print(); derivedObject.print(); system("pause"); return 0; } void baseClass::print() const { cout << x << " " << str << endl; } baseClass::baseClass(string s, int a) { str = s; x = a; } void derivedClass::print() const { cout << "Derived class: " << y << endl; baseClass::print(); } derivedClass::derivedClass(string s, int a, int b) : baseClass("Hello Base", a + b) { y = b; }
- in c++ , fix all bugs or mistakes in code and explain in comments what was wrong and how you fix it (there can be problems with semi-columns, curly braces, included libraries, wrong usage of functions, inproper conversion of datatypes and etc.) Comment all changes in code and show the outputWrite a program in C++ that allows the user to enter the values to assign a card's suit (commonly implemented as an enumeration — Hearts, Clubs, Diamonds, Spades) from the keyboard. You cannot use a menu. Your program must read the user's choice directly into the card suit variable (of an enum type). (Note: You cannot overload operators for built-in types, but enumerations are, technically, user-defined types. Therefore you can overload input/output operators for them.) This proof of conceptapplication will help show your programming team that the bridge game you are designing can accept bids directly from the player without having to rely on a clumsy menu interface. An example program interaction might look something like this: $ ./suitenter.out Welcome to the Card Suit Entering Program!!! What is the suit of your card? hearts You have a heart! Don't wear it on your sleeve..! Another card? y What is the suit of your card? s So, you have a spade! Dig me a hole out back, won't you?…Answer the question with C - language. Question. In the following code, assume that all function calls are successful. void sigusr1_handler(int sig) { } int main(void) { pid_t child; if ((child = fork()) == 0) { struct sigaction sa; sa.sa_handler = sigusr1_handler; sa.sa_flags = 0; sigemptyset(&sa.sa_mask); sigaction(SIGUSR1, &sa, NULL); while (1) { printf("working ...\n"); sleep(1); } } else { //line 19 sleep(30); } // line 22 return 0; } (a) If you run the above program can it create either an orphan or a zombie process? Explain how. (b) Insert statements in only the part of the code related to the parent process (Lines 19–22) and function siguse1_handler() so that the child process would end after about 30 seconds of running. Clearly indicate where you insert any statements. thank you for your time
- 6. In Java, you have the opportunity to either use a predefined function/method or write a user-defined function/method. In this discussion, provide at least three criteria that would be used to develop an appropriate method of your choice and the rationale behind the selection of these criteria.Write a program in C++ that allows the user to enter the values to assign a card's suit (commonly implemented as an enumeration — Hearts, Clubs, Diamonds, Spades) from the keyboard. You cannot use a menu. Your program must read the user's choice directly into the card suit variable (of an enum type). (Note: You cannot overload operators for built-in types, but enumerations are, technically, user-defined types. Therefore you can overload input/output operators for them.)What are the differences and the similarities between a call-by-value parameter and a constant call-by-reference parameter? Declarations that illustrate these follow.void callByValue(int x);void callByConstReference(const int& x);