[H3O+1] = 10-PH[OH-1] = 10-pOH[H3O+1][OH1] = 10-14pH- log [H3O+1]=%3DpOH = - log [OH-]pH + pOH = 14%3D%3DWhat will be the pH if 0.00150 moles of HCl is added to 1.00L of water ? The reaction gives theconversion factorHCI + H2OH3O+1 + CI1start: 0.00150equil:O A. 1.5000В. 2.5223C. 2.824D. 3.125Е. 6.502

Given :- No.of moles of HCl in 1.00L of water = 0.00150 mol To calculate :- pH of solution

Answered: What will be the pH if 0.00150 moles of…

What will be the pH if 0.00150 moles of HCI is added to 1.00 L of water ? The reaction gives the conversion factor HCI + H2O H30+1 + CI1 start: 0.00150 equil:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter14: Acids And Bases

Section: Chapter Questions

Problem 52E: At 40.C the value of Kw is 2.92 1014. a. Calculate the [H+] and [OH] in pure water at 40.C. b. What...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

[H3O+1] = 10-PH
[OH-1] = 10-pOH
[H3O+1][OH1] = 10-14
pH
- log [H3O+1]
=
%3D
pOH = - log [OH-]
pH + pOH = 14
%3D
%3D
What will be the pH if 0.00150 moles of HCl is added to 1.00L of water ? The reaction gives the
conversion factor
HCI + H2O
H3O+1 + CI1
start: 0.00150
equil:
O A. 1.5000
В. 2.5223
C. 2.824
D. 3.125
Е. 6.502

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