What will be the value stored in the variable "s" after executing the following code segment? double values[3] [2] = {1.5,2.3,5.1,7.4}; double s=0; for (int x=0; x<2; x++) s+=values[1] [x];
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- For this assignment please use 2 arrays. Write a program DiscreteDistribution.java that will take an integer command-line argument m, followed by a sequence of positive integer command-line arguments a1,a2,…,ana1,a2,…,an, and will print m random indices (separated by whitespace), choosing each index i with probability proportional to ai.Consider the following C++ code fragment: int a = 3; int b = 2; double r = a/b; Suppose we want r to have the value 1.5, rather than 1. Which cast operator can be used in the third line to achieve this effect? a. static cast b. dynamic cast c. reinterpret cast d. none of the aboveWrite a program in C/C++ that reads N number of nonnegative decimal numbers from a user and creates a hash table to store the numbers. The output of the program displays the order of the numbers in the hash table. The program then prompts the user to enter a target value. The program searches the target value to the hash table, and displays the search outcome. For simplicity, let’s assume that N = 6 and the size of the hash table is 10. Use this hash function in your code h(k) = 2k+3 where k is the key value. Use linear probe method for collision resolution. Example test run Test Run 1: Enter 6 elements: 3 2 9 6 11 13 Hash table order: 13 9 - - - 6 11 2 - 3 Enter the target: 1111 is located at index: 6 Test Run 2: Enter 6 elements: 3 2 9 6 11 13 Hash table order: 13 9 - - - 6 11 2 - 3 Enter the target: 1515 is not in the table
- JAVA File read write and string manipulation data1.txt(down below) 4,5-t 2,4-d 20-p7int 2D 2nd 2 1080 &c 10-p7int 10th 11-p7int 12-p7int 16-p7int 18-p7int 1st 2,4,5-t 2,4-d 20-p7int 2D 2nd 30-30 3D 3-D 3M 3rd 48-p7int 4-D 4GL 4H 4th 5-p7int 5-T 5th 6-p7int 6th 7-p7int 7th 8-p7int 8th 9-p7int 9th @ @' @- @&M @&P @. @.@.@. @.B. @.B.@. @.C. @.D. @.D.C. @.F. @.F.@.M. @.G. @.H. @.I. @.I.@. @.I.D. @.L. @.L.P. @.M. @.M.@. @.M.D.G. @.N. @.p. @.r. @.R.C.S. @.U. @.U.C. @.V. @.w. @.W.O.L. @/C @/F j54rs54y54d J54rs54yit54 j54rs54yit54s J54rs54ym@n j54rs54ys j54rs54y's J54rs54yvill54 j54rt J54rubb@@l J54rubb@l J54rus@l54m J54rus@l54mit54 j54rvi@ j54rvin j54rvin@ j54rvin54 J54rvis J54rk J54S J54sh J54sh54r J54smin54 j54sp54r J54sp54rs54n J54ss J54ss@ J54ss@b54ll j54ss@k5454d J54ss@lin J54ss@lyn j54ss@my j54ss@mi54s J54ss@myn J54ss@min54 j54ss@nt J54ss54 J54ss54@n j54ss54d J54ss5454 J54ss54y J54ss54lyn J54ss54lt7n J54ss54n j54ss54s J54ssi J54ssy J54ssic@ J54ssi54 kikkl54 kikkl54d kikkl54s…Write a program named Search.java that uses a function called search_string to check whether a string exists in the array or not. 1- The array of strings is iterated using a for loop and the value at every index is compared with the value to be searched in the array. 2- A boolean variable is set if any array value matches with the string. 3- At the end of the loop, this boolean variable is checked to determine if the array contains the string. Hint: You may need to import java.util.Arrays then use Arrays.toString, String equals(). The ouput should look like what is pictured below. Please provide an editable code that is easy to copy and paste.void radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPS
- Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 import java.util.Scanner; public class CourseGradePrinter {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ P.S. The answer came out wrong the first try 7 9 11 10 10 11 9 7EnterPlease help me code in java: Write a program that reads two files “Data1.txt”, “Data2.txt”; adding their corresponding elements produces an output file “output.txt”. If the number of elements are not equal, fill the elements of the smaller file up with “0” s. Sample output: Elements of the “Data1.txt”: 3 5 7 8 9 Elements of the “Data2.txt”: 45 11 Elements of the “Output.txt”: 48 16 7 8The following code does not compile. Why not? What is upsetting the compiler? int a = 10; int b = 20; int sum = IntStream.of(1, 2, 3, 4, 5) .map(n -> n + b - (++a)) .sum();
- write program code in java: Write a program that reads two files “Data1.txt”, “Data2.txt”; Then add their corresponding elements and produce an output file “output.txt”. If the number of elements are not equal, fill the elements of the smaller file up with “0” s. Sample output: Elements of the “Data1.txt”: 3 5 7 8 9 Elements of the “Data2.txt”: 45 11 Elements of the “Output.txt”: 48 16 7 8In Python, The function concatAltChars takes a string parameter s and a boolean parameter even; the function concatenates together either the even-position characters of s or the odd-position characters of s, depending on whether even is True, or False, respectively. The accumulated string is returned. For example, the even-indexed characters of "HANOVER" are at indexes 0, 2, 4, and 6: H N V R. So, concatAltChars("HANOVER", True) returns the string result "HNVR". But concatAltChars("HANOVER", False) returns the string result "AOE". For example: Test Result s = "goldfinches" print(concatAltChars(s, True)) glfnhs s = "A" print(concatAltChars(s, True)) A s = "A" print(concatAltChars(s, False))I need to store data from a text file into an object array then store the object array into a linked list using Java Example of file im trying to convert: //String //Int //Double //Double //Int Joe 101 17.2 10.0 4 Alex 97 15.3 12.5 7 Maria 85 16.4 18.2 9 Steve 153 23.5 16.3 8