When 300.0ml of 0.700M Na2S and 200.0ml of 0.900M Fe(NO3)3 solutions are mixed together the reaction below occurs: 3Na2S(aq) + 2Fe(NO3)3(aq) ----> Fe2S3(s) 6NaNO3(aq) What will be the maximum theoretical yield of precipitate, in moles?
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When 300.0ml of 0.700M Na2S and 200.0ml of 0.900M Fe(NO3)3 solutions are mixed together the reaction below occurs:
3Na2S(aq) + 2Fe(NO3)3(aq) ----> Fe2S3(s) 6NaNO3(aq)
What will be the maximum theoretical yield of precipitate, in moles?
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